- #1
gijoel
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Homework Statement
I've got a doppler shift question about calculating the frequency heard by a receiver moving 5.0m/s towards a sound source that is emitting 3000Hz sound. I assumed speed of sound is 343 m/s for an air temperature of 20C.
Homework Equations
Freceiver = Fsender((V + Vreceiver)/V) Where V is speed of sound in air
The Attempt at a Solution
After calculating the sound I get 3000Hz x (348/343)
Which equals 3000hz x 1.015
=3043.731...Hz
If I round off to one or two significant digits like the problem states then I get 3000Hz. Which doesn't make sense. What am I missing here? Is there some rule the over rides significant digits for these types of answers?