- #1
unscientific
- 1,734
- 13
How did they arrive at this expression? I understand the ##Q^2## term in the nominator and the ##r = r_0 (A)^{\frac{1}{3}}## term in the denominator. Where did the ##\frac{\alpha}{2}## term come from?
Putting in Z=40, A=100 gives ##3.3 \times 10^{14} J##, not ##65 MeV##.
The energy term should be of the form ## \frac{1}{4\pi \epsilon_0} \frac{Q^2}{R}##.
Also, shouldn't the energy barrier ##E_{barrier}## decrease with increasing nucleon number?
However, the text seems to imply the opposite.
Last edited: