Simple partial fractions help (warning complex analysis :P )

In summary, the conversation discusses finding the partial fraction equivalent for Vc(s) in a RLC circuit. The attempt at a solution involves setting up a system of equations and solving for the unknown coefficients. There is a small rounding error present, but the overall process is correct. The poster also expresses confusion about how their post ended up in a different thread, but thanks the responder for their help.
  • #1
trickae
83
0

Homework Statement


the question can be ignored - it involves laplace and Z transforms of RLC ckts.

Code:
Vc(s) =          0.2
           -----------------
             s^2 + 0.2s + 1

find the partial fraction equivalent such that it is :
Code:
  -j(0.1005)     +    j (0.1005)
--------------    ------------------
s + 0.1-(0.995)    s + 0.1 + j(0.995)

Homework Equations



none

The Attempt at a Solution


Code:
      0.2                      A                     B
---------------  =  ---------------------  +  -------------------
s^2 + 0.25 + 1      s + (0.1 - j(0.995)))     s + (0.1 + j(0.995))

0.2 = A(s + 0.1 + j(0.995)) + B(s + (0.1 - j0.995))

0.2 = As + A(0.1 + j(0.995)) + Bs + B(0.1 - j0.995)

so As + Bs = 0
or (A + B) = 0
or A = -B
so
0.2 = j(0.995A) - j(0.995B)

somethings not right - if i evaluate this I don't get anywhere near the answer
 
Last edited:
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  • #2
Well, check this:

(s + 0.1 - I 0.995)(s + 0.1 + I 0.995) = 1.00002 + 0.2 s + s²

there is a small inaccuracy ... but nothing more.
Solve your last equation and turn to another exercice.

What does that become:

0.2 = j(0.995A) - j(0.995B)

if A=-B ?
 
Last edited:
  • #3
sorry dude I'm still a little confused.

thats just a rounding error from the J term.
 
  • #4
I just wanted to say that, except for decimals, you did it correctly.
You should solve the last equation and conclude.
 
  • #5
thanks man i got it now - actually my next question is a little off topic ... but how did i get a post stuck in this thread?

https://www.physicsforums.com/showthread.php?t=166823&page=2

I don't understand the thread whatsover. ANyways thanks for the help i actually got the answer i'l put it up when i get home.
 

Related to Simple partial fractions help (warning complex analysis :P )

1. What are simple partial fractions?

Simple partial fractions are fractions that can be broken down into smaller, simpler fractions with a common denominator. They are commonly used in complex analysis to simplify integrals and functions.

2. How do you solve problems involving simple partial fractions?

To solve problems involving simple partial fractions, you first need to factor the denominator of the fraction. Then, you set up a system of equations to solve for the unknown coefficients in each fraction. Finally, you combine the fractions to get the final answer.

3. What is the purpose of using simple partial fractions in complex analysis?

The purpose of using simple partial fractions in complex analysis is to simplify complex integrals and functions. By breaking down a complex fraction into simpler fractions, it becomes easier to integrate and analyze the function.

4. How do you handle complex numbers in simple partial fractions?

Complex numbers can be handled in simple partial fractions by separating them into their real and imaginary parts. These parts can then be treated as separate fractions, with the real and imaginary coefficients being solved for separately.

5. Are there any common mistakes to avoid when working with simple partial fractions?

One common mistake when working with simple partial fractions is forgetting to reduce the fractions to their lowest terms before solving for the coefficients. This can lead to incorrect answers and make the problem more complex than it needs to be.

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