Smith Chart: Find Input Impedance for Antenna Problem

In summary, the input impedance to the transmission line can be found using a Smith Chart. The parallel combination of a 40ohm resistor and a capacitor with Xc = -j25 can be expressed as admittances and normalized by dividing by 0.02. By plotting the normalized admittance and traveling along the chart, the input impedance can be found. Alternatively, the normalised values of the parallel R and Xc can be found by dividing each by 50 and their reciprocals can be plotted to find the input impedance. Finally, the normalized impedance values can be multiplied by 50 to obtain the actual values.
  • #1
maearnie
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Homework Statement


An antenna is modeled by a 40ohm resistor in parallel with a capacitor with Xc = -j25. The antenna is fed
by a lossless 50ohm signal line 0.15 wavelengths long. Use a Smith Chart to find the input impedance to
the transmission line.

Homework Equations


The Attempt at a Solution


The solution is in the attached file but i don't understand it after obtaining the admittance.
 

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  • #2
maearnie said:

Homework Statement


An antenna is modeled by a 40ohm resistor in parallel with a capacitor with Xc = -j25. The antenna is fed
by a lossless 50ohm signal line 0.15 wavelengths long. Use a Smith Chart to find the input impedance to
the transmission line.

Homework Equations


The Attempt at a Solution


The solution is in the attached file but i don't understand it after obtaining the admittance.
This is how the person worked it out. First the parallel R and Xc can be expressed as admittances, by simply taking the reciprocal of each. Then they are normalised by dividing by 0.02, which is the value at the centre of the chart (it is the Zo of the line, 50 Ohms or 1/50=0.02 Siemens). Plot the normalised admittance, then notice the VSWR, which is the radial distance, and we rotate around the chart at this radius towards the generator for a distance of 0.15 lambda. This point gives the admittance at the generator, and we travel across the chart to the opposite point to obtain the normalised impedance at the generator. Multiply R and X by 50 to obtain the required values.
But I think the following is easier:
Find the normalised values of the parallel R and Xc by dividing each by 50.
Find their reciprocals, which gives you normalised admittance.
Plot the point and then travel diametrically across the chart and mark the normalised impedance of the load.
Note the VSWR at this point - the radius.
Rotate around the chart at this radius towards the generator for 0.15 lambda and this point gives you the normalised input impedance of the line.
Multiply the normalsed impedance values by 50 to obtain the actual values.
 
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  • #3
tech99 said:
This is how the person worked it out. First the parallel R and Xc can be expressed as admittances, by simply taking the reciprocal of each. Then they are normalised by dividing by 0.02, which is the value at the centre of the chart (it is the Zo of the line, 50 Ohms or 1/50=0.02 Siemens). Plot the normalised admittance, then notice the VSWR, which is the radial distance, and we rotate around the chart at this radius towards the generator for a distance of 0.15 lambda. This point gives the admittance at the generator, and we travel across the chart to the opposite point to obtain the normalised impedance at the generator. Multiply R and X by 50 to obtain the required values.
But I think the following is easier:
Find the normalised values of the parallel R and Xc by dividing each by 50.
Find their reciprocals, which gives you normalised admittance.
Plot the point and then travel diametrically across the chart and mark the normalised impedance of the load.
Note the VSWR at this point - the radius.
Rotate around the chart at this radius towards the generator for 0.15 lambda and this point gives you the normalised input impedance of the line.
Multiply the normalsed impedance values by 50 to obtain the actual values.
Thank you very much! i was wondering why they multiplied 50 instead of multiplying it. hahaha
 

What is a Smith Chart?

A Smith Chart is a graphical tool used in electrical engineering to help analyze and design radio frequency circuits. It is a polar plot of the complex reflection coefficient, which is a measure of how much of an incident wave is reflected at a certain point in a transmission line.

How do you use a Smith Chart to find input impedance for an antenna problem?

To find the input impedance for an antenna problem using a Smith Chart, you would first plot the load impedance on the chart. Then, you would draw a line from the center of the chart through the load impedance point, representing the transmission line. Next, you would find the point on the line where it intersects with the constant resistance circle, which represents the characteristic impedance of the transmission line. This intersection point gives the input impedance of the antenna.

What is the characteristic impedance of a transmission line?

The characteristic impedance of a transmission line is the ratio of voltage to current at any point along the line. It is represented as a resistance value and is dependent on the physical properties of the transmission line, such as its length, diameter, and material.

Why is the Smith Chart useful for solving antenna problems?

The Smith Chart is useful for solving antenna problems because it allows for quick and accurate visualization of complex impedance values. With its polar plot, it is easy to see the magnitude and phase of the reflection coefficient, which is crucial in designing and analyzing antenna systems.

Can the Smith Chart be used for other types of circuits besides antenna problems?

Yes, the Smith Chart can be used for other types of circuits besides antenna problems. It can be used to analyze and design any circuit with transmission lines, such as amplifiers, filters, and matching networks. It is also useful for impedance matching and adjusting circuit parameters to achieve desired performance.

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