S11 of Ideal Transmission line on a Smith Chart

In summary, the S11 response of an ideal transmission line terminated with a load impedance of 90 ohms and a characteristic impedance of 50 ohms traces out a circle on the smith chart. This can be explained using the equations for Zin and S11, where the expression for Zin does not equal ZL when l, the length of the transmission line, is set to zero. This may suggest that there is a mistake in the calculations.
  • #1
Xyius
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4

Homework Statement


An ideal transmission line is terminated with a load impedance of 90 ohms and has a characteristic impedance of 50 ohms. Why does it's S11 response trace out a circle on the smith chart?

Homework Equations


[tex]Z_{\text{in}}=Z_0\frac{Z_0+j Z_L \tan(\beta l)}{Z_L+j Z_0 \tan(\beta l)}[/tex]
[tex]S_{11}=\Gamma=\frac{Z_{\text{in}}-Z_0}{Z_{\text{in}}+Z_0}[/tex]

The Attempt at a Solution


So my thought was that perhaps I can plug the expression for ##Z_{\text{in}}## into the expression for ##S_{11}## and simplify and get an expression for a circle. After many tries, the closest thing I can come up with is the following.

[tex]S_{11}=\frac{e^{-j\beta l}}{(Z_0+Z_L)}\left[ (Z_L-Z_0)\cos(\beta l)- j (Z_L+Z_0) \sin(\beta l) \right][/tex]

This kind of looks like the equation for an ellipse inside the brackets, but the term out front kills it.

Am I doing this all wrong?
 
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  • #2
If you set l, the length of the transmission line to zero, then ZIN should equal ZL. But it doesn't in your first expression. Look again at your expression for ZIN.
 

1. What is the significance of S11 in an ideal transmission line on a Smith Chart?

S11, also known as the reflection coefficient, represents the amount of signal that is reflected back from the load to the source in a transmission line. In an ideal transmission line, S11 is equal to zero, meaning that there is no reflection and all of the signal is transmitted to the load.

2. How is S11 calculated on a Smith Chart?

S11 is calculated by finding the ratio of the reflected voltage to the incident voltage at a particular point on the Smith Chart. This can be done using the formula S11 = (Vr/Vi) * e^(-j2betaL), where Vr is the reflected voltage, Vi is the incident voltage, beta is the propagation constant, and L is the length of the transmission line.

3. What does it mean when S11 is a negative value on a Smith Chart?

A negative value for S11 on a Smith Chart indicates that the reflected signal is out of phase with the incident signal. This can occur when the load is either capacitive or inductive, and the amount of phase shift can be determined by the position of the point on the Smith Chart.

4. How does the position of S11 on a Smith Chart affect the performance of a transmission line?

The position of S11 on a Smith Chart can provide valuable information about the performance of a transmission line. If S11 is close to the center of the Smith Chart, it means that the line is well matched and there is minimal reflection. However, if S11 is closer to the outer edge of the Smith Chart, it indicates a mismatch and potential signal loss or distortion.

5. What factors can cause S11 to deviate from an ideal value of zero on a Smith Chart?

Several factors can contribute to a non-zero value for S11 on a Smith Chart. These include impedance mismatches, variations in the transmission line's characteristic impedance, and the presence of discontinuities or imperfections in the line. Environmental factors such as temperature and humidity can also affect S11.

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