So, is it correct to measure centrafugal force due to a planet's rapid orbit?

In summary, the conversation discusses the effects of the planet's rotation and orbit on its centrifugal force and gravity. It is mentioned that a fast rotation can result in a significant centrifugal effect and that the closer a planet is to its host star, the greater the centrifugal force. The example of the planet Corot-7b is given, where its fast rotation causes a centrifugal effect of 14.8g, resulting in a difference in gravity between the day and night sides. However, the overall gravity is still greater than the centrifugal force. The conversation also mentions the formula used to calculate gravity from centrifugal force and explains that there is no net outward force when a planet is in orbit around a sun.
  • #1
calis
30
0
Hello
i was concerned about how fast should Earth spin so that on equator gravity would be 0 due to centrafugal force i got 84 minutes - full spin

since it is more like 24 hours than on equator currently centrafugal force is 0,039g
but there is also one smaller centrafugal force coming from orbiting the sun and it is 0.005g
non feelable. barely measurable...

the problem is that the closer you get to host star the biger the centrafugal force from rotating the star become. for mercury it is 0,04g

but there is also a smallest known planet corot-7b with 1.7 Earth diameters slightly denser and 23 times closer to its star than mercury to sun. which makes it have its full year ONLY in 20hours and 29 minutes
it turns out that spining so fast makes a centrafugal effect of 14,8g which is abolutelly enormous well the planets gravity is still slightly bigger 16g
but this fact is bringing in some weird consequences

1. the planet is most likely face locked.
2. the gravity at the backside is 1.2 g
3. the gravity at the front side is 30.8g WOW
4. the funniest thing is what the gravity at the sides are
it is actually somewhere inbetween but it is not pointing down but at an angel away from star.
so it would feel like climbing down a hill. now if you happen to have a bicycle and you are at the dayside . you can always take a ride to night side just releasing the brakes.

is it correct measuring centrafugal force due to planets rapid orbit.

i used formula for calculating gravity from centrafugal force like this
g=R*(pi*rpm/30)^2 where R-radius in meters, rpm -ratePerMinute
 
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  • #2
If a planet is in orbit around a sun, there is no net "outward force". Remember there is the gravity of the Sun to account for. It is like the object sitting at the equator with the Earth rotating in 84 min. The tendency to fly off is canceled by the gravity pulling in.

That is not to say that there would not be a difference between the Sun facing side and its opposite, but this would be due to their different distances from the Sun. For Corot-7b this works out to a difference of less than 2/100 g.
 

1. What is the difference between gravity and centrifugal force?

Gravity is a force of attraction between two objects due to their mass, while centrifugal force is a fictitious force that arises when an object is in a rotating frame of reference.

2. How do gravity and centrifugal force affect objects?

Gravity pulls objects towards the center of the Earth, while centrifugal force pulls objects away from the center of rotation.

3. Which force is stronger, gravity or centrifugal force?

Gravity is typically stronger than centrifugal force. However, the strength of centrifugal force can vary depending on the speed of rotation and the distance from the center of rotation.

4. How are gravity and centrifugal force related?

Gravity and centrifugal force are both fundamental forces that affect the motion of objects. In some cases, they can work together to produce a net force on an object, while in other cases they may cancel each other out.

5. Can we experience both gravity and centrifugal force on Earth?

Yes, we experience both gravity and centrifugal force on Earth. Gravity keeps us grounded and prevents us from flying off into space, while centrifugal force can be experienced on amusement park rides or when driving around a curved road.

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