- #1
supernova1203
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The question is asking us to determine weather there is a Li+ Ion or Sr+2 ion in the solution
We are using the precipitation method
Using various solubility tables I determined that Sr+2 ion is not soluble with the sulphate ion
SO-24
the course book uses the compound Na2SO4
my question is, they intentionally use sulphate ion because they know if there is Sr+2 ion in solution, there will be a precipitate, if there isn't then there will be no precipitate, but why did they use sodium? Couldnt they have used any group 1 Metal? since any group 1 metal would have been soluble with Li ion?
We are using the precipitation method
Using various solubility tables I determined that Sr+2 ion is not soluble with the sulphate ion
SO-24
the course book uses the compound Na2SO4
my question is, they intentionally use sulphate ion because they know if there is Sr+2 ion in solution, there will be a precipitate, if there isn't then there will be no precipitate, but why did they use sodium? Couldnt they have used any group 1 Metal? since any group 1 metal would have been soluble with Li ion?