Solve Bragg Diffraction: n(λ)/2sinθ

[oldspice1212]

Bragg diffraction of microwaves lab.
Hey guys I have a quick question so for bragg diffraction the formula is 2dsin(theta) = n(lambda).
So I have to solve for d, which is d = n(lambda)/(2sin(theta)), but here is the problem: I'm not entirely sure what theta is, as I'm using a graph with 2 peak values, so would theta be just the peak value, and the first peak is n = 1, and peak 2 is n = 2?

Thanks

 

[Greg Bernhardt]

Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?

 

[oldspice1212]

Hey no problem, thanks for checking that means a lot to me.
I figured it out eventually, thank you very much though!

 

[nasu]

Yes, the angle in the formula will be the peak value.
Regarding the order of the diffraction peak, it is possible that the second peak is the second order of the first. But it is not necessary.
What was your sample?

 

[HalfLostAndSearching]

for your question! In Bragg diffraction, theta represents the angle of incidence of the microwaves on the crystal lattice. It is typically measured from the normal to the crystal surface. In your experiment, you can determine the angle of incidence by measuring the distance between the peak values on your graph and using the known wavelength of the microwaves. Once you have determined the angle, you can plug it into the formula d = n(lambda)/(2sin(theta)) to solve for the spacing between the crystal lattice planes (d). Keep in mind that the peak values on your graph correspond to different values of n, so you will need to use the correct value of n for each peak to calculate the corresponding d value. I hope this helps!