Solve Simple RL Circuit: Find and Sketch y(t)

In summary, the conversation discusses a DC transient circuit analysis problem where the switch is closed for a long time and then opened at t=0. The question is to find and sketch the current y(t). There are two possible scenarios discussed - one where the 2nd inductor is fully charged at t=0 and the other where it is not charged at all. The latter seems to be more likely based on the voltage across the 2nd inductor always being 0V before the switch opens. However, this presents a problem since both 5A and 0A would be flowing in the same loop at t=0. Therefore, it is considered an ill-posed problem.
  • #1
kdinser
337
2

Homework Statement


The switch is closed for a long time and opened instantaneously at t=0. Find and sketch the current y(t).


I haven’t had a class where I needed to do DC transient circuit analysis for over a year, so this simple thing is giving me some problems.


The way I see it, either:

1. The inductor that is parallel with the switch (2nd inductor) is fully charged at t=0 and opening the switch has no effect on the current y(t) and y(t) = 5 amps at all time t. Which is what my solution using laplace transforms is showing and what pspice seems to confirm.

OR

2. The 2nd inductor has not been charged at all at t=0 because all the current is running through the closed switch. This would mean that I'm making some kind of serious error when I set up my equation, because when I try to make this assumption, I get a final current below 5 amps at t=infinity so I know that can't be right.

Thanks for any help, if I'm wrong on both accounts, I'll start posting equations so I can get this figured out.


Just noticed that my jpg says pending approval. To draw this circuit, put a 10V voltage source in series with a 1H inductor, a 2 ohm resistor, and a 2H inductor in a closed loop. Then add a switch that opens at t=0 and is closed at t < 0 in parallel with the 2H inductor.
 

Attachments

  • circuit.JPG
    circuit.JPG
    11.6 KB · Views: 669
Last edited:
Physics news on Phys.org
  • #2
I think it is more of the latter, that the 2H inductor is not charged before t = 0. My reason for saying so is as follows: The voltage across the 2H is always 0V before the switch opens. Then Ldi/dt = 0, or in other words, there is no change in the current across this inductor, hence it remains at 0A.

This, however, presents a huge problem when the switch opens since you would then have both 5A (over the 1H) and 0A (over the 2H) flowing in the same loop at t = 0 (which is impossible, of course). That being so, I would rate this problem as an ill-posed problem.
 
  • #3


I would recommend reviewing the fundamentals of DC transient circuit analysis and using the appropriate equations and methods to solve this problem. It is important to understand the behavior of inductors and how they respond to changes in current and voltage. It is also useful to double check your calculations and assumptions to ensure accuracy in your solution. If you are still having trouble, seeking help from a professor or tutor may be beneficial. Additionally, using simulation software such as PSpice can help verify your solution and provide a visual representation of the current behavior.
 

Related to Solve Simple RL Circuit: Find and Sketch y(t)

What is a simple RL circuit?

A simple RL (resistor-inductor) circuit is an electrical circuit that contains a resistor and an inductor, connected in series. It is used to study the behavior of inductors in a circuit and to analyze the flow of current through the circuit.

How do you solve a simple RL circuit?

To solve a simple RL circuit, you need to use Kirchhoff's voltage law and Ohm's law to set up and solve a differential equation. This equation can then be solved using mathematical techniques such as separation of variables or Laplace transforms.

What is y(t) in a simple RL circuit?

In a simple RL circuit, y(t) represents the current through the circuit at a given time t. This current is determined by the values of the resistor and inductor in the circuit, as well as the initial conditions of the circuit.

How do you sketch y(t) for a simple RL circuit?

To sketch y(t) for a simple RL circuit, you can plot the current on a graph as a function of time. The shape of the graph will depend on the values of the resistor and inductor in the circuit, as well as the initial conditions.

What are some real-world applications of simple RL circuits?

Simple RL circuits have many real-world applications, such as in power supplies, electric motors, and generators. They are also used in electronic filters and inductance-based sensors. In addition, the behavior of RL circuits is important in understanding more complex circuits and systems.

Similar threads

  • Engineering and Comp Sci Homework Help
Replies
3
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
3
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
10
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
13
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
7
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
8K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
28
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
7
Views
4K
  • Introductory Physics Homework Help
Replies
6
Views
189
Back
Top