Solving for Index of Refraction: 110 Degrees Angle

AI Thread Summary
The discussion revolves around calculating the index of refraction of varnish based on the angle of reflection and incidence. The problem states that the angle between the incident and reflected rays is 110 degrees, leading to confusion about how to apply the correct formulas. Participants clarify that the angle of incidence equals the angle of reflection, and the polarizing angle must be determined from the given information. The correct approach involves using the relationship between the angles and applying Brewster's angle formula. A diagram is recommended to visualize the angles and solve for the index of refraction accurately.
matt72lsu
Messages
94
Reaction score
0

Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?
 
Physics news on Phys.org
Well because it is reflected, it sounds like you have a case of total internal reflection. You'll need to use sinC = 1/n.
 
matt72lsu said:

Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?

Ah so close. You are correct in using the Brewster's angle formula. However notice the trick in the problem. They tell you the angle between the rays NOT the angle the rays make with normal.
 
so would i do 180-110 or something like that? the angle thing is messing me up
 
matt72lsu said:
so would i do 180-110 or something like that? the angle thing is messing me up
No.
During reflection angle of incidence is equal to angle of reflection. In the problem, the sum of the angle of incidence and angle of reflection is given. from that find the angle of incidence which is the polarizing angle.
 
Yes what rl.bhat said is correct. If you are still having trouble thinking about it, try drawing a diagram and setting the reflected and incident angles to the normal equal. Also set the angle between the two rays equal to 110.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top