Solving for the final velocity of an object thrown off of a Martian Volcano

In summary, the tallest volcano in the solar system is the 19 km tall Martian volcano, Olympus Mons. An astronaut drops a ball off the rim of the crater and the free fall acceleration of the ball remains constant at 4 m/s2. Using the equation Vf = Vo + at, the time for the ball to reach the crater floor is 97.468s. The magnitude of the velocity with which the ball hits the crater floor is 389.872 m/s.
  • #1
garcia1
27
0
The tallest volcano in the solar system is the
19 km tall Martian volcano, Olympus Mons.
An astronaut drops a ball off the rim of the
crater and that the free fall acceleration of the
ball remains constant throughout the ball’s
19 km fall at a value of 4 m/s2. (We assume
that the crater is as deep as the volcano is tall,
which is not usually the case in nature.)
Find the time for the ball to reach the crater
floor.
Answer in units of s.

Find the magnitude of the velocity with which
the ball hits the crater floor.
Answer in units of m/s.



Homework Equations



Vf = Vo +at


The Attempt at a Solution



I simply plugged in values from the first problem's answer, 97.468s, along with the given acceleration and implied initial velocity to make:

Vf = (-4m/s)(97.468s) = -389.872 m/s

This was wrong though, so I'm wondering where I screwed up along the way.
 
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  • #2
The solution is correct.
 
  • #3
The problem asks how long it takes for an object to fall 19 km on Mars. Your equation displayed deals only with calculation of velocities. Use the right equation, get the right answer.
 
  • #4
Disregard my last post.
 
  • #5
The question asks for the magnitude of the velocity. Magnitudes are positive values...
 

What is the equation for calculating the final velocity of an object thrown from a Martian volcano?

The equation for calculating the final velocity of an object thrown from a Martian volcano is v = u + gt, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity on Mars, and t is the time elapsed.

How does the acceleration due to gravity on Mars affect the final velocity of an object thrown from a volcano?

The acceleration due to gravity on Mars is approximately 3.7 m/s^2, which is much lower than the acceleration due to gravity on Earth. This means that objects thrown from Martian volcanoes will have a slower final velocity compared to objects thrown from Earth's volcanoes.

What factors can affect the initial velocity of an object thrown from a Martian volcano?

The initial velocity of an object thrown from a Martian volcano can be affected by several factors, including the force used to throw the object, the angle at which the object is thrown, and any air resistance present in the Martian atmosphere.

Can the final velocity of an object thrown from a Martian volcano be greater than the initial velocity?

Yes, it is possible for the final velocity of an object thrown from a Martian volcano to be greater than the initial velocity. This can occur if the object is thrown at a high enough angle or if there is a strong enough force applied to the object.

Are there any other factors that need to be considered when solving for the final velocity of an object thrown from a Martian volcano?

Yes, other factors that may need to be considered include the mass and shape of the object being thrown, as well as the surface conditions of the volcano (such as the slope and terrain).

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