Solving Problem with Derivatives as Initial Conditions

In summary, the conversation discusses solving equations with derivatives as initial conditions and compares it to solving equations with traditional boundary conditions. The use of separation of variables and Fourier series is mentioned as a way to solve these types of problems.
  • #1
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Homework Statement



I've been given equations that have derivatives as initial conditions, rather than things like u(0,t)=u(L,t)=0

Things like this:

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Homework Equations






The Attempt at a Solution


I can solve problems with condition like u(0,t)=u(L,t)=0 but how do you solve them with derivatives?

Wouldn't for lamba=0 X''=0 -> X=c1*x+c2 and applying x'(0)=0 make X=c2?
 
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  • #2
You would follow the exact same process (of separation of variables).

The reason [itex]\lambda = 0[/itex] doesn't work is the same reason it doesn't work when you use the standard boundary conditions you've listed above.

The end result is you end up with an equation for X as [itex]X(x) = c_1 \cos{\sqrt{\lambda}x}[/itex]. What does this say about [itex]\lambda[/itex]? To finish the problem, you need to apply the idea of Fourier series and use your initial condition.
 

Related to Solving Problem with Derivatives as Initial Conditions

What is the concept of using derivatives as initial conditions in problem solving?

The concept of using derivatives as initial conditions in problem solving is based on the idea that the derivative of a function at a specific point represents the rate of change of the function at that point. By using derivatives as initial conditions, we can determine the behavior of the function at that point and use it to solve problems.

How are derivatives used as initial conditions in problem solving?

To use derivatives as initial conditions, we first find the derivative of the given function at the specified point. This derivative is then used to set up an equation or system of equations that can be solved to determine the unknown variable or variables in the problem.

What types of problems can be solved using derivatives as initial conditions?

Derivatives as initial conditions can be used to solve a variety of problems, especially those involving rates of change or optimization. Some common examples include finding the maximum or minimum value of a function, determining the velocity or acceleration of an object at a specific time, and solving related rates problems.

Are there any limitations to using derivatives as initial conditions in problem solving?

While derivatives can be a powerful tool in problem solving, there are some limitations to their use. Derivatives may not accurately represent the behavior of a function at a given point if the function is not continuous or differentiable at that point. Additionally, using derivatives as initial conditions may not always yield a solution, especially if the problem is complex or involves multiple variables.

What are some tips for effectively using derivatives as initial conditions in problem solving?

To effectively use derivatives as initial conditions, it is important to have a solid understanding of the underlying concepts of derivatives and their applications. It can also be helpful to draw graphs or diagrams to visualize the problem and its solution. Additionally, checking your answer using different methods or approaches can help to ensure the accuracy of the solution.

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