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Vir
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Homework Statement
I have 1.5 kgs of silicon with temperature 40 degrees celsius. It is dropped into 3 kgs of water holding temperature 25 degrees celsius. The system is heat isolated from the environment and the final temperature of the system is 26.2 degrees celsius. I need to find the specific heat capacity of silicon.
Homework Equations
\begin{equation}
C = \frac{\mathrm{d}Q}{\mathrm{d}T}
\end{equation}
The Attempt at a Solution
Energy lost by metal = energy gained by water:
\begin{equation}
\Delta U_{m} = \Delta U_{w}
\\
\Delta T_{m} m_{m} C_{m} = \Delta T_{w} m_{w} C_{w}
\\
C_m = \frac{\Delta T_{w} m_{w} C_{w}}{\Delta T_{m} m_{m} }
\end{equation}
Now I have one unkown, the specific heat capacity of water. Assuming water to be an ideal gas(which i guess kinda works at lower pressures) I have:
\begin{equation}
C_w = nR
\end{equation}
where $n$ are the amount of moles of water. But here I need the molar mass of water, so that's just another unkown. Is there any way to solve this problem with the given data?