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declan.B
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Homework Statement
A 30.0g block of ice at 0.00°C is dropped into 500.0g of water at 45.0°C. If the process was carried out in an iron container with a mass of 150g what would the final temperature be?
Homework Equations
Q=mc(T2-T1)
Heat Lost = Heat Gained
Specific Heat of Water: 4200
Specific Heat of Ice: 2100
Specific Heat of Iron: 460
The Attempt at a Solution
I understand how to find the final temperature of the water without the iron container using the equation above (mc(T2-T1)=mc(T2-T1)) and i get (34.5 degrees), however I'm completely stuck when it comes to adding the iron mass into the equation.
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