Speed and rest energy of a particle collision

In summary: Well, technically the electron and positron are not massless, but at these energies they are nearly massless.
  • #1
arella
16
0
Homework Statement
If I'm given an electron that collides with an anti-electron with momentum in the opposite direction, which produces another particle, P, how to I find the speed of particle P? And how to I find the rest energy?

The initial momentum of the electron is: 9.06GeV/c

Initial momentum of the anti-electron is: 3.1 GeV/c (which would be negative here)

I am given a rest energy of .511 MeV for both electron and anti-electron.
Relevant Equations
K=(gamma-1)mc^2?

Rest energy I know is mc^2.
I honestly have no clue where to start, any help would be great.
 
Physics news on Phys.org
  • #2
arella said:
Homework Statement:: If I'm given an electron that collides with an anti-electron with momentum in the opposite direction, which produces another particle, P, how to I find the speed of particle P? And how to I find the rest energy?

The initial momentum of the electron is: 9.06GeV/c

Initial momentum of the anti-electron is: 3.1 GeV/c (which would be negative here)

I am given a rest energy of .511 MeV for both electron and anti-electron.
Relevant Equations:: K=(gamma-1)mc^2?

Rest energy I know is mc^2.

I honestly have no clue where to start, any help would be great.
What quantities are conserved in this situation? Which of those conserved quantities might be useful?
 
  • #3
jbriggs444 said:
What quantities are conserved in this situation? Which of those conserved quantities might be useful?
Energy and momentum are conserved, right? I'm just not sure of the equations I should use to solve for v exactly?
 
  • #4
arella said:
Energy and momentum are conserved, right? I'm just not sure of the equations I should use to solve for v exactly?
Yes. Energy is conserved. You can write down an equation for that.
Yes. Momentum is conserved. You can write down an equation for that.
 
  • #5
arella said:
Energy and momentum are conserved, right? I'm just not sure of the equations I should use to solve for v exactly?
That's two equations, so write them. Create variables as necessary for unknowns.
 
  • #6
haruspex said:
That's two equations, so write them. Create variables as necessary for unknowns.
My issue is that I am unfamiliar with the equations and have no clue what to put down for them, especially with relativistic circumstances. Could you help show me the equations?
 
  • #7
arella said:
My issue is that I am unfamiliar with the equations and have no clue what to put down for them, especially with relativistic circumstances. Could you help show me the equations?
Start with the momentum equation. Starting momentum on the left hand side. Can you figure out what goes there?
 
  • #8
jbriggs444 said:
Start with the momentum equation. Starting momentum on the left hand side. Can you figure out what goes there?
mv*gamma is p, yet since I'm approaching this thinking the electron and anti-electron are massless, I'm unsure of how the equations work.
 
  • #9
arella said:
mv*gamma is p, yet since I'm approaching this thinking the electron and anti-electron are massless, I'm unsure of how the equations work.
I think you are missing the forest for the trees. The total momentum at the beginning does not require any knowledge of relativity or quantum physics. We are given the initial momenta.
 
  • #10
arella said:
approaching this thinking the electron and anti-electron are massless
Wrong thought. You are given rest energies.
 
  • #11
arella said:
mv*gamma is p, yet since I'm approaching this thinking the electron and anti-electron are massless, I'm unsure of how the equations work.

Well, technically the electron and positron are not massless, but at these energies they are nearly massless.

PS As long as you understand why, you can treat them as effectively massless particles. That should simplify things.
 
Last edited:

What is the speed of a particle collision?

The speed of a particle collision can vary greatly depending on the particles involved and the conditions of the collision. In particle accelerators, collisions can reach speeds close to the speed of light, while in natural collisions, the speeds may be much lower.

What is rest energy in a particle collision?

Rest energy refers to the energy that a particle possesses when it is at rest. It is equivalent to the mass of the particle multiplied by the speed of light squared (E=mc^2). In a particle collision, this rest energy can be converted into kinetic energy and other forms of energy.

How is the speed of a particle collision calculated?

The speed of a particle collision can be calculated using the principles of conservation of energy and momentum. By measuring the energy and momentum of the particles before and after the collision, the speed of the collision can be determined.

What factors affect the speed of a particle collision?

The speed of a particle collision can be affected by several factors, such as the mass and velocity of the particles involved, the type of collision (elastic or inelastic), and the presence of any external forces or fields.

Why is the speed and rest energy of a particle collision important?

Understanding the speed and rest energy of a particle collision is crucial in many areas of physics, including particle physics, astrophysics, and nuclear physics. It helps scientists to better understand the fundamental properties of matter and the forces that govern the universe.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
919
  • Introductory Physics Homework Help
Replies
20
Views
979
  • Introductory Physics Homework Help
Replies
4
Views
451
  • Introductory Physics Homework Help
Replies
17
Views
370
  • Introductory Physics Homework Help
Replies
20
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
25
Views
831
  • Introductory Physics Homework Help
Replies
9
Views
856
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
851
Back
Top