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Homework Statement
A 10 kg block is displaced 20 mm and released. If damping coefficient is 100 N.s/m,
how many cycles will be executed before amplitude is reduced to 1 mm or below? The stiffness
of the spring is k=20000 N/m.
Homework Equations
The Attempt at a Solution
I first moved the mass to the inner radius and equated the Kinetic Energy of the system.
Ke1 = Ke2
Where i found m2 is 4m1
Next i equated the kinetic energy of the system and equated that to :
[itex]\frac{1}{2}[/itex]*m[itex]_{eq}[/itex]*v[itex]^{2}[/itex]
[itex]\frac{1}{2}[/itex]*m[itex]_{2}[/itex]v[itex]^{2}[/itex] + [itex]\frac{1}{2}[/itex]I[itex]\frac{V^{2}}{r^{2}}[/itex]= [itex]\frac{1}{2}[/itex]* m[itex]_{eq}[/itex]*v[itex]^{2}[/itex]
meq = m2 + [itex]\frac{I}{r^{2}}[/itex] where m2is 4*m1
I then substituted the numbers in and found Meq= 190
Next to find the amplitude i found the damping ratio of the system
[itex]\zeta[/itex] =[itex]\frac{c}{Cc}[/itex]
Cc = 2*m*Wn
Wn = [itex]\sqrt{\frac{K}{M}}[/itex]
Wn= [itex]\sqrt{\frac{20000}{190}}[/itex] Wn = 10.26
Cc = 2(190) * (10.26) = 3899 ∴ [itex]\zeta[/itex] = [itex]\frac{100}{3899}[/itex]
[itex]\zeta[/itex] = 0.0256
Under damped system E.O.M =
X(t) = e[itex]^{-\zeta*W_{n}*t}[/itex] { x[itex]_{o}[/itex]Cos(w[itex]_{d}[/itex]t) + [itex]\frac{x^{.}+W_{n}*X_{0}}{w_{d}}[/itex]*Sin(w[itex]_{d}[/itex]t) }
I'm trying to find the t value that would make X(t) be less than 1mm, I'm not sure how i would do that without just picking random values of t, as the equation doesn't seem solvable just for t.
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