Spring Scale Problem: Finding Time w/ Force & Mass

In summary, the conversation discusses using a spring scale to pull a 1.5 kg object on a horizontal frictionless surface with a constant horizontal force of 1.3 N. The object starts from rest and covers a distance of 2.7 m, and the question is asking for the reading of the stopwatch. The solution involves using the equations F=ma and ΔX=VoT+.5aT^2, with Vo being 0, to calculate the acceleration and distance traveled. The resulting answer is 2.49. There is also mention of finding the value of k using the equation F=kx.
  • #1
DrDanger
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0

Homework Statement


You use a spring scale to pull a 1.5 kg object on a horizontal frictionless surface with a constant horizontal force of 1.3 N (according to the scale reading). You use a stopwatch to time how long it takes the object, starting from rest, to cover a distance of 2.7 m. What is the reading of the stopwatch?

Homework Equations


F=-KX
F=ma
[tex]\Delta X=VoT+.5aT^2[/tex]

The Attempt at a Solution


So I did a=F/m to get the acceleration then plugged that into [tex]\Delta[/tex] X=VoT+.5aT^2 and Vo is equal to 0. After i plugged it all in I got 2.49, is that right? For some reason it seems wrong.
 
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  • #2
On a side note, is possible to find k using f=kx?
 
  • #3


As a scientist, it is important to check your units and make sure they are consistent. In this case, you are using a force of 1.3 N and a mass of 1.5 kg, which means your units for acceleration should be m/s^2. However, when you plug in the values, you get a value of 0.867 m/s^2, which is not consistent with the given force and mass.

To solve this problem, you can use the equation F=ma to find the acceleration, which is equal to 1.3 N / 1.5 kg = 0.867 m/s^2. Then, you can use the equation \Delta X=VoT+.5aT^2 and plug in the given values for distance (2.7 m) and acceleration (0.867 m/s^2) to solve for the time, T. This will give you a time of approximately 2.23 seconds.

Therefore, the reading of the stopwatch would be 2.23 seconds. It is important to double check your calculations and units to ensure accuracy and consistency in your results.
 

Related to Spring Scale Problem: Finding Time w/ Force & Mass

1. How do you use a spring scale to find time with force and mass?

To use a spring scale to find time with force and mass, you first need to gather your materials: a spring scale, an object of known mass, and a stopwatch. Next, hang the object on the spring scale and record the reading on the scale. Then, release the object and use the stopwatch to time how long it takes for the object to reach the ground. Finally, use the formula t = √(2m/gF) to calculate the time, where t is time, m is mass, g is the acceleration due to gravity, and F is the force measured by the spring scale.

2. What is the formula for finding time using a spring scale?

The formula for finding time using a spring scale is t = √(2m/gF), where t is time, m is mass, g is the acceleration due to gravity, and F is the force measured by the spring scale.

3. Can a spring scale be used to measure time directly?

No, a spring scale is not designed to measure time directly. It is used to measure force and cannot accurately measure time on its own.

4. How does the force on a spring scale affect the time it takes for an object to fall?

The force on a spring scale does not directly affect the time it takes for an object to fall. However, the force measured by the spring scale can be used to calculate the time using the formula t = √(2m/gF). This means that a greater force measured by the spring scale will result in a shorter time for the object to fall.

5. Are there any factors that can affect the accuracy of using a spring scale to find time?

Yes, there are several factors that can affect the accuracy of using a spring scale to find time, such as air resistance, the accuracy of the stopwatch, and human error. It is important to conduct the experiment in a controlled environment and to use precise measurements to minimize these factors and ensure accurate results.

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