You set up a heat balance: heat given off = heat taken upYeahaight said:
Well, heat taken up would be - Q = c water*m1*(t2-t1)?BvU said:
In ideal conditions, steam cools down inside the mass of water until becoming water itself.Yeahaight said:
So you want to find out how much heat is given off by starting out with x kilograms of water vapour at 100 ##^\circ##C and ending up with ... ?Yeahaight said:
Steam is created when water is heated to its boiling point, which is 100 degrees Celsius at standard atmospheric pressure. When steam is injected into water, it transfers its heat energy to the water molecules, causing them to vibrate faster and increase in temperature.
The temperature of the water will increase as more steam is injected into it. This is because the steam carries heat energy, and the more steam that is injected, the more heat energy is transferred to the water, causing its temperature to rise.
The amount of steam needed to heat a specific amount of water to 100 degrees Celsius depends on the initial temperature of the water and the specific heat capacity of the water. However, as a general rule, it takes approximately 540 calories of heat energy to convert 1 gram of water at 0 degrees Celsius to steam at 100 degrees Celsius.
No, at standard atmospheric pressure, water will boil and turn into steam at 100 degrees Celsius. The temperature will not increase beyond this point, as the heat energy will be used to convert the water into steam rather than increase its temperature.
The steam will continue to exist as steam at 100 degrees Celsius as long as it is in contact with the water. However, if the steam is removed from the water and allowed to cool, it will condense back into liquid water and release its heat energy into the surrounding environment.