- #1
tigerlily5709
- 1
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1.Hey guys, I've been struggling with this one for an hour and it SHOULD NOT be this hard for me.
A 15kg picture hangs from a hook on the wall. What is the tension in each wire if one is at a cartesian angle of 220° and one is at a cartesian angle of 320°?
2.
So my physics 20 teacher told me to break it into vertical and horizontal components. I solved for one of my tensions and then tried to substitute into my second equation...that's when things get scary. Please help!
3. I tried:
0N = -147.15N + Ft1 (sin 220°) + Ft2 (sin 320°)
I was trying to solve for Ft1 first.
A 15kg picture hangs from a hook on the wall. What is the tension in each wire if one is at a cartesian angle of 220° and one is at a cartesian angle of 320°?
2.
So my physics 20 teacher told me to break it into vertical and horizontal components. I solved for one of my tensions and then tried to substitute into my second equation...that's when things get scary. Please help!
3. I tried:
0N = -147.15N + Ft1 (sin 220°) + Ft2 (sin 320°)
I was trying to solve for Ft1 first.