The angle and distance of a projection - Grade 11 physics

In summary, the conversation discusses the trajectory of a water balloon fired from a water cannon and its ability to hit a target. The calculation for the horizontal distance of the balloon is provided, showing that it will not hit the target. It is suggested to decrease the speed of the balloon to make it hit the target, although adjusting the angle may have been a more accurate choice. The conversation also mentions the ease of adjusting the speed versus the angle on a real water cannon.
  • #1
CAT 2
44
1

Homework Statement


A water balloon is fired 34 m/s from a water cannon, which is aimed at an angle of 18° above the ground. The centre of the cannon's target (which has a radius of 1.0m) is painted on the asphalt 42m away from the water cannon.
a) Will the balloon hit the target? Justify your response with calculations that indicate where the water balloon will land.
b) make one suggestion about how to adjust the water cannon so that the water balloon will hit the target. Justify your choice.

Homework Equations


This equation is used for finding horizontal distance.
Dh = v1^2 Sin 2(angle)/ a

The Attempt at a Solution


. https://www.physicsforums.com/file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image002.png v1 = 34 m/s
angle = 18°
a = 9.8 m/s^2 [down]

Find the horizontal projected distance of the projected balloon

Dh = v1^2 Sin 2(angle)/ a
Dh = (34 m/s)^2 (Sin2(18°)/ 9.8 m/s^2
Dh = 69.3 meters

Since the distance to the target is 42 meters and the water balloon traveled 69.3 meters, the balloon did not hit the target.To make it hit the target, the speed needs to be decreased.

Dh = v1^2 Sin 2(angle)/ a
42m = v1^2 (Sin2(18°)/ 9.8 m/s^2
42m = v1^2 (0.05998)
√700 = v1
26.5 m/s = v1To make the balloon hit the target the speed needs to be decreased to 26.5m/s.Is this done correctly?
 
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  • #2
Looks good.

What other parameter might you vary to change the range of the water canon? Which parameter might be easier to vary accurately (on a real water canon)?
 
  • #3
The angle would probably have been a better choice, but it was easier to adjust the speed. They don't exactly specify which one to change, (speed or angle). Do you think it will matter?
 
  • #4
CAT 2 said:
The angle would probably have been a better choice, but it was easier to adjust the speed. They don't exactly specify which one to change, (speed or angle). Do you think it will matter?
Probably not in a purely technical sense. But I would think that practically speaking, a canon would have targeting swivels (altitude and azimuth) built into its design, and simple to adjust. Changing the "charge" of a shot might be more cumbersome.
 
  • #5
Yeah, that's true. Thanks for your help.
 

1. What is the difference between angle and distance in a projection?

Angle refers to the direction in which the object is projected, while distance refers to how far the object travels in that direction.

2. How do you calculate the angle and distance of a projection?

The angle and distance of a projection can be calculated using trigonometric equations, such as sine, cosine, and tangent, along with the initial velocity and angle of projection.

3. Does the angle and distance of a projection affect the trajectory of the object?

Yes, the angle and distance of a projection directly impact the trajectory of the object. Changing these parameters can result in different paths and landing points for the object.

4. What is the optimal angle and distance for maximum projection distance?

The optimal angle for maximum projection distance depends on the initial velocity of the object. However, a 45-degree angle is generally considered the optimal angle for maximum distance in a projectile motion.

5. How can the angle and distance of a projection be applied in real-life situations?

The concept of angle and distance of a projection is commonly used in sports, such as basketball, soccer, and golf, to determine the angle and force needed to make a successful shot or kick. It is also used in engineering and construction projects to calculate the trajectory of objects being projected, such as rockets or projectiles.

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