- #1
rwooduk
- 762
- 59
Homework Statement
Homework Equations
RL = 20 log10(Vrms) - OCV
For this hydrophone OCV = -211dB
The Attempt at a Solution
1. RL = 20 log10(Vrms) - OCV
RL = 20 log10(3.5mV) - (-211)
RL = 161dB re uPa
2. 20 log10 (uPa) = dB
Pa = 10^(dB/20) X 10^(-6) = 10^(161/20) X 10^(-6) = 112 kPa
3. ?
4. ?
5. Impedance
So I'm basically stuck in how to convert pascals to watts, and watts per cm^2. Would I use the volume of the water? but wouldn't that be cm^3? why is power measured in W/cm^2? and how do I convert the original 20W into this unit?
Thanks for any help with this!
p.s. If I use the online converter here:
http://www.sengpielaudio.com/calculator-soundlevel.htm
I get 112 kPa = 194 db(SPL) = 25118864 W/m^2 = 2511 W/cm^2 which is HUGE, the value should be ~10W/cm^2 maximum