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LCSphysicist
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- Homework Statement
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- Relevant Equations
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The question is simply why i can't use ∂U/∂V = -P?
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When taking partial derivatives, it is important to know what variables are being kept constant.LCSphysicist said:The question is simply why i can't use ∂U/∂V = -P?
Internal energy in thermodynamics refers to the total energy contained within a system, including the kinetic and potential energy of its particles. It is a measure of the system's microscopic energy and is affected by factors such as temperature, pressure, and composition.
Internal energy and temperature are directly proportional to each other. As the temperature of a system increases, so does its internal energy, and vice versa. This relationship is described by the equation E = mc2, where E is the internal energy, m is the mass of the system, and c is the speed of light.
Internal energy and enthalpy are both measures of energy in a system, but they differ in how they take into account the energy required to maintain a constant pressure. Enthalpy includes this energy, while internal energy does not. In other words, enthalpy takes into account the work done by the system on its surroundings, while internal energy does not.
Pressure can affect the internal energy of a system in two ways. First, an increase in pressure can cause the particles in the system to move closer together, resulting in an increase in the system's internal energy. Second, changing the pressure of a system can also change its temperature, which in turn affects its internal energy.
According to the first law of thermodynamics, energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the internal energy of a system can change, but it cannot be created or destroyed. It is always conserved in a closed system.