- #1
damien88
- 16
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A strain-gauge bridge is made up of four resistive elements, each element having an unstrained
resistance equal to R, as shown in the diagram below. When a strain is applied to the bridge
elements R2 and R4 increase in resistance by an amount ΔR, whereas R1 and R3 decrease by ΔR,
where ΔR/R is proportional to the applied strain. Find the Thévenin equivalent of the circuit in its
strained state looking into nodes x and y.
I can't seem to cut the image so hopefully I can describe it. Top node is Vbridge, left and right nodes are x and y respectively and bottom node is ground.
3. I have R2+ΔR//R1-ΔR= R^2-(ΔR)^2/2R=(approx)R/2. Same will apply for R3 and R4 to give R/2. Equivalent resistors are now in parallel to give R? Would this be correct?
Thanks in advance
resistance equal to R, as shown in the diagram below. When a strain is applied to the bridge
elements R2 and R4 increase in resistance by an amount ΔR, whereas R1 and R3 decrease by ΔR,
where ΔR/R is proportional to the applied strain. Find the Thévenin equivalent of the circuit in its
strained state looking into nodes x and y.
I can't seem to cut the image so hopefully I can describe it. Top node is Vbridge, left and right nodes are x and y respectively and bottom node is ground.
3. I have R2+ΔR//R1-ΔR= R^2-(ΔR)^2/2R=(approx)R/2. Same will apply for R3 and R4 to give R/2. Equivalent resistors are now in parallel to give R? Would this be correct?
Thanks in advance