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eq123
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this problem is killing me! [calculation of electron transition]
i've been trying to solve this problem.. the answer should be 7.. my answer is 0.7 !
What is the value of n_i for an electron that emits a photon of wavelength 93.14 nm when it returns to the ground state in the H atom?
my solution..
n_f=1
λ=93.14 nm×(10^(-9) m)/(1 nm)=93.14×10^(-9) m
∆E=hν=hc/λ=(6.63×10^(-34)×3.00×10^8)/(93.14×10^(-9))≈2.14×10^(-18)
∆E=-2.18×10^(-18) (1/(n_f^2 )-1/(n_i^2 ))
2.14×10^(-18)=-2.18×10^(-18) (1/1^2 -1/(n_i^2 ))
-2.14/2.18=1-1/(n_i^2 )
1.982= 1/(n_i^2 )
n_i^2=0.5045
n_i=√0.5045≈0.7
n_i = n initial
n_f = n final
λ = wavelength ( lambda )
∆E = energy of the transition
h = plank's constant
ν = frequency ( nu )
c = speed of light
if reading the solution is an issue.. just past it in microsoft word and activate the equation mode..
i've been trying to solve this problem.. the answer should be 7.. my answer is 0.7 !
What is the value of n_i for an electron that emits a photon of wavelength 93.14 nm when it returns to the ground state in the H atom?
my solution..
n_f=1
λ=93.14 nm×(10^(-9) m)/(1 nm)=93.14×10^(-9) m
∆E=hν=hc/λ=(6.63×10^(-34)×3.00×10^8)/(93.14×10^(-9))≈2.14×10^(-18)
∆E=-2.18×10^(-18) (1/(n_f^2 )-1/(n_i^2 ))
2.14×10^(-18)=-2.18×10^(-18) (1/1^2 -1/(n_i^2 ))
-2.14/2.18=1-1/(n_i^2 )
1.982= 1/(n_i^2 )
n_i^2=0.5045
n_i=√0.5045≈0.7
n_i = n initial
n_f = n final
λ = wavelength ( lambda )
∆E = energy of the transition
h = plank's constant
ν = frequency ( nu )
c = speed of light
if reading the solution is an issue.. just past it in microsoft word and activate the equation mode..
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