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Homework Statement
show that ((tanx - sinx)/sin^3x) = (1/(cosx - cos^2x))
Homework Equations
sin^2 = 1-cos^2v
cos^2 = 1-sin^2v
The Attempt at a Solution
On the left hand side: I plugged in sinx/cosx for tanx. I then divided both the numerator and denominator by sinx to get ((1/cosx - 1)/ sin^2x).
After this point I got stuck. I tried plugging in 1-cos^2x for sin^2x and simplifying the fraction, but it didn´t work. Do you guys have any tips on how to progress?