- #1
reganw
- 19
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A rude tourist throws a peach pit horizontally with a 7.0 m/s velocity out of an elevator cage. The ground is 17 m below. How long will it take for the pit to land if the elevator is moving upward at a constant 8.5 m/s velocity?
d=Vot + 1/2at2
My attempt that continuously doesn't work is:
-17=(8.5)(t)+1/2(-9.8)(t2)
-17=8.5t - 4.9t2
The answer is 2.92s.. I'm just not quite sure how to get there. Please show all the steps in your solution.. I'm drawing a blank on how to solve for t!
Thank you!
d=Vot + 1/2at2
My attempt that continuously doesn't work is:
-17=(8.5)(t)+1/2(-9.8)(t2)
-17=8.5t - 4.9t2
The answer is 2.92s.. I'm just not quite sure how to get there. Please show all the steps in your solution.. I'm drawing a blank on how to solve for t!
Thank you!
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