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Ste
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Hi all, apologies if this is in the wrong section but I thought it would be ok as it's kind of homework related.
I'm 35 years old and I'm trying to learn a bit about physics. With that in mind I thought I'd start at the G.C.S.E level seeing as I can't remember a thing from school. I borrowed a book from the library and the information is sinking in ok, but there's one equation that I'm having a spot of bother with. I'll do my best to explain and hopefully someone will be able to help.
I'm currently learning about how the area under a velocity-time graph is equal to distance travelled. The book says that the equation for working out the area of a triangle, 1/2 base x height, is equal to 1/2at^2 However when I work out the two equations using the following information I get two different answers.
When t=4s
And V=5m/s
For the area of a triangle equation I get the answer s=10
For 1/2at^2 I get the answer s=12.5
It seems that I'm either working out the equation incorrectly, or I've somehow misunderstood the book. Any help would be great, thanks.
I'm 35 years old and I'm trying to learn a bit about physics. With that in mind I thought I'd start at the G.C.S.E level seeing as I can't remember a thing from school. I borrowed a book from the library and the information is sinking in ok, but there's one equation that I'm having a spot of bother with. I'll do my best to explain and hopefully someone will be able to help.
I'm currently learning about how the area under a velocity-time graph is equal to distance travelled. The book says that the equation for working out the area of a triangle, 1/2 base x height, is equal to 1/2at^2 However when I work out the two equations using the following information I get two different answers.
When t=4s
And V=5m/s
For the area of a triangle equation I get the answer s=10
For 1/2at^2 I get the answer s=12.5
It seems that I'm either working out the equation incorrectly, or I've somehow misunderstood the book. Any help would be great, thanks.