- #1
brawler234
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A box is moving at a constant velocity. 250N of applied force is acting on a box while 250N of friction is acting on it on the opposite direction. If the box travels 4 meters in the same direction as the applied force, how much work is done?
I know that work = force * displacement.
Is the force in the equation supposed to be the net force (which would make work 0J) or just the applied force in the same direction of motion (which would make work 1000J)?
[Moderator's note: Moved from a technical forum and thus no template.]
I know that work = force * displacement.
Is the force in the equation supposed to be the net force (which would make work 0J) or just the applied force in the same direction of motion (which would make work 1000J)?
[Moderator's note: Moved from a technical forum and thus no template.]
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