- #1
fxdung
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Consider symmetry SO(1,3)xU(1)=SU(2)xSU(2)xU(1) and puting a local spontaneous broken symmetry:
Φ→exp(iαaτa)exp(iαaτa)exp(i(β/2))Φ
The field Φ acquires vacuum expectation value: <Φ>=(0,v).
Then ΔL=½(0 v)(gCμaτa+gAμaτa+
½g'Bμ)2(0 v)T.Then we find out three massive boson,one massless photon and two massless vector boson corresponding with 8 components of gravitation field hμν
Is that correct?
Φ→exp(iαaτa)exp(iαaτa)exp(i(β/2))Φ
The field Φ acquires vacuum expectation value: <Φ>=(0,v).
Then ΔL=½(0 v)(gCμaτa+gAμaτa+
½g'Bμ)2(0 v)T.Then we find out three massive boson,one massless photon and two massless vector boson corresponding with 8 components of gravitation field hμν
Is that correct?