Using a double angle formula with Snell's Law

In summary: To solve for a, you substitute sin(2a)cos(a) into Snell's law and use the inverse of cosine function.
  • #1
smeiste
36
0

Homework Statement


A light ray is incident from air onto a glass surface with an index of refraction n = 1.56. Find the angle of incidence for which the corresponding angle of refraction is one-half the angle of incidence. Both angles are defined with the normal to the surface.


Homework Equations


n = sin a1/sin a2 (Snell's Law)

sin(a + b) = (sin a x cos b) + (cos a x sinb)

sin(2a) = 2 sin a cos a

The Attempt at a Solution



Somehow you plug in the double angle formula into snells law. but I don't understand how this is a down. a breakdown of the equations used to solve problem would be extremely helpful :)
 
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  • #2
The angle of incidence is 2a, the angle of refraction is a. Plug into Snell's law.

ehild
 
  • #3
but then how do you solve for a?
 
  • #4
Show your equation.

ehild
 
  • #5
sin(a)/sin(2a) = 1.56
 
  • #6
smeiste said:
sin(a)/sin(2a) = 1.56

What happens if you apply the sine double angle formula here?
 
  • #7
Your equation is actually incorrect. by Snell's formula,
sin a = 1.56Apply the duble angle formula to sin (2a) to get 2sin(a)cos(a). since a does not equal an integral multiple of pi, you can divide out sin(a). From there, you can find that cos(a) = 0.321
Use the inverse of cosine function to solve for a = 71.306 degrees.
 
Last edited:
  • #8
if sin a = 1.56, how do you apply the double angle formula?
 
  • #9
bobquantum said:
Your equation is actually incorrect. by Snell's formula,
sin a = 1.56Apply the duble angle formula to sin (2a) to get 2sin(a)cos(a). since a does not equal an integral multiple of pi, you can divide out sin(a). From there, you can find that cos(a) = 0.321
Use the inverse of cosine function to solve for a = 71.306 degrees.

Snell's Law:
[tex] \frac{sin(\theta 1)}{sin(\theta 2)} = \frac{v1}{v2} = \frac{n2}{n1} [/tex]
 
  • #10
im so confused.. could someone just show the steps on how to solve it? i think much better in equations than words.
 
  • #11
Take Snell's law as I wrote it above (You can ignore the velocity ratio, I only included it for completeness. It's not needed for this problem). Substitute the given values for the angles and indexes of refraction. What do you get?
 
  • #12
isnt that what i wrote before? sin a/sin 2a = 1.56/1.
 
  • #13
sorry, i see. sin2a/sina = 1.56/1
 
  • #14
ah ha! so sin 2a = 2sinacosa and the sins cancel out, giving you a final equation of cos a = 0.78. thanks very much everyone!
 

1. How can a double angle formula be used with Snell's Law?

The double angle formula can be used with Snell's Law to simplify calculations involving the angle of refraction when a light ray passes through two media with different refractive indices. It allows for the use of trigonometric identities to express the angle of refraction in terms of the incident angle and the refractive indices of the two media.

2. What is the double angle formula for Snell's Law?

The double angle formula for Snell's Law is given by sin(2θ) = 2sin(θ)cos(θ), where θ represents the angle of incidence or refraction.

3. Why is the double angle formula useful when working with Snell's Law?

The double angle formula is useful because it simplifies the calculations involved in determining the angle of refraction. It allows for the use of basic trigonometric identities, which are often easier to work with than the original Snell's Law equation.

4. Can the double angle formula be used with any type of light passing through different media?

Yes, the double angle formula can be used with all types of light, including visible light, UV light, and infrared light, passing through any two media with different refractive indices. It is a general formula that applies to all types of light and media.

5. Are there any limitations to using the double angle formula with Snell's Law?

One limitation is that the double angle formula only applies when the light ray is passing through two media with different refractive indices. If there are more than two media involved, a different formula or approach may be needed. Additionally, the double angle formula assumes that the light ray is passing through the media at a single interface and does not take into account any reflections or other complexities that may occur.

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