Vapour pressure/solubility of small and big grain surfaces and corners

In summary, when a condensed phase (solid or liquid) is in an immiscible fluid (gas or liquid), it has surface energy which is determined by the combined surface area of the condensed phase. In the case of liquids, the surface energy is equalized due to surface tension, resulting in a curved and smooth surface. However, in the case of solids, the crystal faces, edges, and corners have different surface energies, leading to an equilibrium shape that minimizes the total surface energy. This can be explained by the Wulff construction method, which uses energy minimization arguments to determine the preferred crystal planes. The paradox lies in how a crystal manages to minimize the total surface energy, despite responding only to local conditions. One possibility
  • #1
snorkack
2,190
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When a condensed phase - solid or liquid - is in an immiscible fluid (gas or liquid), it has surface energy. Several small pieces of condensed phase have bigger combined surface than one bigger piece of the phase of the same volume, and thus bigger energy.

In case of liquid, the surface of a drop is curved and smooth. Due to surface tension, the curvature of a liquid drop equalizes. Which means that the surface energy is equal everywhere on the drop, and so is the vapour pressure or solubility.

But a solid grain possesses crystal faces, edges and corners. These must always enclose the volume of the crystal.
How does a crystal ensure that the binding energy of a molecule to a corner is identical to the binding energy of the same molecule to any other corner, edge or face of the same crystal - BUT smaller than binding energy of the same molecule to equally flat face of a bigger crystal?
 
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  • #2
Different crystallographic faces of crystals have in general different surface energies, due to differences in bonding or atom density. The equilibrium shape of a crystal corresponds to a minimization of the total surface energy.
 
  • #3
Lord Jestocost said:
Different crystallographic faces of crystals have in general different surface energies, due to differences in bonding or atom density. The equilibrium shape of a crystal corresponds to a minimization of the total surface energy.
The paradox I see here is the issue of total/local energy minimization. In case of a spherical liquid drop, the matter is easy - the drop adopts curvature which ensures uniform surface energy at every specific point. But in case of crystal - the action of a molecule evaporating or dissolving from a surface, edge or corner or depositing at another such place should respond only to local conditions, therefore how does it manage to minimize the total surface energy?
 
  • #4
One possibility is surface diffusion at higher temperatures.
 
  • #5
This does not resolve the paradox. Because since the equilibrium is between initial state of molecule attached to one place on the crystal and final state with the molecule attached to another place on the same crystal, it is irrelevant whether the intermediate state has the molecule in a gas phase, dissolved in a solvent or moving around along the surface.
 
  • #6
snorkack said:
The paradox I see here is the issue of total/local energy minimization.
Where is here a paradox.

In case of solids, surface energy minimization can be attained if the constituents are mobile enough to rearrange themselves in reasonable times (normally at high temperatures).

The Wulff construction is a method to determine the equilibrium shape of a crystal of fixed volume inside a separate phase (usually its saturated solution or vapor). Energy minimization arguments are used to show that certain crystal planes are preferred over others, giving the crystal its shape.

https://en.wikipedia.org/wiki/Wulff_construction
 

1. What is vapour pressure?

Vapour pressure is the pressure exerted by the gaseous form of a substance in equilibrium with its liquid or solid form at a given temperature. It is a measure of the tendency of a substance to escape from its liquid or solid state and enter the gas phase.

2. How does the size of a grain surface affect vapour pressure?

The size of a grain surface can affect vapour pressure in several ways. Smaller grain surfaces have a higher surface area to volume ratio, which means there are more sites for molecules to escape from the solid phase and enter the gas phase. This can result in a higher vapour pressure for smaller grain surfaces compared to larger ones.

3. What is the relationship between solubility and vapour pressure?

There is an inverse relationship between solubility and vapour pressure. As the solubility of a substance increases, its vapour pressure decreases. This is because when a substance is more soluble in a liquid, more of its molecules remain in the liquid phase and less are able to escape into the gas phase.

4. How do corners affect the solubility of a substance?

Corners, or edges, of a substance have a higher surface energy compared to flat surfaces. This can result in a higher solubility of the substance at corners, as the higher surface energy makes it easier for molecules to escape from the solid phase and enter the liquid phase.

5. Can the vapour pressure and solubility of a substance change with temperature?

Yes, both vapour pressure and solubility are affected by temperature. As temperature increases, the vapour pressure of a substance also increases. This is because higher temperatures provide more energy for molecules to escape from the solid or liquid phase and enter the gas phase. Similarly, the solubility of a substance generally increases with temperature, as higher temperatures provide more energy for molecules to break free from the solid phase and dissolve in a liquid.

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