Can you explain what the magnitude of that force would be, and why?PhanthomJay said:
As always, use free body diagrams and the equilibrium equations. The tension in a rope passing through an ideal pulley is the same on both sides of the pulley. So the force of the wall on the rope must have a magnitude of T, acting left. By summing external forces of the system in the x direction = 0, the horizontal force of the wall on the beam must also be T, acting right, since that it is the only place where another external force can exist. The shear and moment values in the beam are the same as in the first case.dmk90 said:
A pulley can change the direction of a force and distribute the load among multiple ropes or cables. This can result in a more complex free body diagram with additional forces acting on the system.
A fixed pulley is attached to a stationary object and only changes the direction of force, while a movable pulley is attached to the moving object and also reduces the amount of force needed to lift the load.
The tension in a rope or cable can be determined by considering the forces acting on the pulley and using the principle of equilibrium to set the sum of the forces equal to zero.
No, a pulley should not be ignored in a free body diagram as it can significantly affect the forces acting on a system and can change the overall equilibrium of the system.
The number of pulleys in a system can affect the number and direction of forces acting on the system, leading to a more complex free body diagram. Additionally, the mechanical advantage of the system can change with the addition of more pulleys.