How Does the Virial Theorem Help Determine Position Uncertainty in a C-H Bond?

In summary: Once you have that, you need to use the Virial theorem to calculate the expectation value of the ground state potential energy. Then, using that information and the fact that the potential energy depends on the square of the position, you can calculate the position uncertainty of the bond length. Finally, you are asked to comment on the validity of assuming a small vibration amplitude in the Harmonic Oscillator mode, given that the C-H bond is about 1 Å.
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jjc43
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Homework Statement



Using paper, pencil and the Virial theorem, calculate the position uncertainty (an estimate of the vibration amplitude) of the H atom in its ground state C-H stretching mode. In more precise language, calculate the bond length uncertainty in a C-H bond due to the C-H stretching mode. First, look up the transition energy of a C-H stretch (you can pick whichever you like, they are all the same to two significant figures). This will allow you to calculate the energy spacing between the = 0 = 1 states. Second, you can use this information to calculate the ground state energy. Next, use this information and the Virial theorem to calculate the expectation value of the ground state potential energy. Because the potential energy a depends on the square of the position it can be used to calculate the position uncertainty of the bond length. Given that the C-H bond is about 1 Å, comment on the validity of assuming a small vibration amplitude in the Harmonic Oscillator mode

Homework Equations


Transition energy=ħ ω
ω=2πcṽ where ṽ is the wavenumber
Ground state energy= ħ ω/2
Virial theorem: vhat=ax^b 2<T> = b<V>

Notes:

-For the Harmonic Oscilator, <x>= 0
variance: Δx= (<x^2>-<x>^2)^(-1/2)
-Virial Theorem as applied to the Harmonic oscilattor says 2<KE> = 2<V>
Then use <Etotal> = <KE> + <V>

The Attempt at a Solution


[/B]
I am not sure about what to use as the wavenumber, I looked at the IR absorption value for the c-h stretch and used 3000cm^-1.

ω=2πcṽ
= 2π(2.998*10^8m/s)*(300000m^-1)
= 5.65*10^14s^-1

Transition energy= ħ ω
= 5.9551*10^-20J

Ground state energy= ħ ω/2
= 2.97755*10^-20J

I am not sure about what to do after this
 
Last edited:
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  • #2
Welcome to PF!

So far, so good. I would suggest that you continue to follow the outline given in the problem statement. What's the next step after finding the ground state energy?
 

1. What is the Virial Theorem and what does it state?

The Virial Theorem is a mathematical relationship that describes the equilibrium state of a system of particles. It states that the average kinetic energy of the particles in a system is equal to the negative of the average potential energy.

2. How is the Virial Theorem used in physics and astronomy?

The Virial Theorem is used in various fields of physics and astronomy to understand the equilibrium state and dynamics of systems. It is particularly useful in studying the behavior of gases, stars, and galaxies.

3. What are the applications of the Virial Theorem?

The Virial Theorem has many applications in physics and astronomy. It can be used to calculate the mass of a galaxy, estimate the size of a star, and understand the behavior of molecular clouds and gas in the interstellar medium.

4. How is the Virial Theorem derived?

The Virial Theorem is derived from the equations of motion and conservation of energy principles. It involves manipulating and combining equations to arrive at the final form of the theorem.

5. Are there any limitations to the Virial Theorem?

Yes, the Virial Theorem has some limitations. It assumes that the system is in equilibrium and that the particles are interacting through inverse square law forces. It also does not take into account the effects of external forces or non-conservative forces.

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