Weight/Satellite Above Earth's Surface

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The weight of a 62.3 kg man in a satellite orbiting at 8.44 x 10^6 m above Earth is not simply calculated by multiplying the acceleration due to gravity (1.82 m/s^2) by his mass, resulting in 113 N. This is incorrect because the astronaut is in a state of free-fall due to the satellite's orbit, which creates a sensation of weightlessness. The calculation assumes he is stationary above Earth, but in orbit, he experiences apparent weightlessness. The distinction between actual weight and apparent weight must be considered, as the effective gravitational force is altered by the satellite's motion. Understanding these dynamics is crucial for accurate weight assessments in orbital environments.
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Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?
 
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sweetpete28 said:
Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?

No doubt that would be his weight if he were held stationary above the Earth at the given altitude, with no angular motion. But he is in orbit, and thus free-fall. If he were to place a spring scale between himself and the downward facing "floor" of the satellite, what do you suppose it would read?
 
sweetpete28 said:
Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?

Just checking that you considered the difference between the distance above the Earth [presumably the surface] and the Radius of the orbit - the distance to the centre of the Warth.

You are then faced with whether you are after the actual weight, or the apparent weight.
 
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