What are the physics/forces behind a bike pedal?

  • Thread starter beterdenu
  • Start date
  • Tags
    Bike Pedal
In summary, the physics and forces behind a bike pedal involve the transfer of energy from the rider's legs to the pedals, which then rotate the crank and ultimately propel the bike forward. This process is made possible by the principles of leverage, torque, and rotational motion. The rider's body weight and position also play a role in determining the force applied to the pedals and the efficiency of the pedaling motion. Additionally, the design and materials of the pedal and crank also impact the overall performance and effectiveness of the pedaling system.
  • #1
beterdenu
4
0
Thread moved from the technical forums, so no Homework Help Template is shown
Hi All,

I am working on a project that mounts an accelerometer to the bike pedal, and requires me to calculate the power that the sensor experiences as the bike is being ridden. However, I am having some trouble understanding the forces that the pedal/sensor experiences.

Essentially, I need to calculate power given the acceleration the sensor experiences, mass of the sensor, and time. Here's what I have right now:

Power = Work/time = ½*m*v^2
Power * Time = ½*m*v^2
v = sqrt(2*Power*t/m)
a = dv/dt = sqrt(Power/2*m*t)
Power = a^2*(2*m*t)

While this does give me power, I don't know if this equation is applicable to my project. I'm also thinking that I need to account for the rotational physics as well, which I am not sure how to do. Could someone explain how I could calculate the power at any given moment?

Thanks
 
Physics news on Phys.org
  • #2
beterdenu said:
Hi All,

I am working on a project that mounts an accelerometer to the bike pedal, and requires me to calculate the power that the sensor experiences as the bike is being ridden. However, I am having some trouble understanding the forces that the pedal/sensor experiences.

Essentially, I need to calculate power given the acceleration the sensor experiences, mass of the sensor, and time. Here's what I have right now:

Power = Work/time = ½*m*v^2
Power * Time = ½*m*v^2
v = sqrt(2*Power*t/m)
a = dv/dt = sqrt(Power/2*m*t)
Power = a^2*(2*m*t)

While this does give me power, I don't know if this equation is applicable to my project. I'm also thinking that I need to account for the rotational physics as well, which I am not sure how to do. Could someone explain how I could calculate the power at any given moment?

Thanks
Welcome to the PF.

Your first two equations have the same RHS but different LHSs. How can that be true? You can use dimensional analysis to double-check equations to look for simple mistakes.

Also, I don't think you can calculate power just based on the acceleration and movement of the pedals. Consider the case where you are pedalling on flat ground versus climbing a hill. You may have the same cadence, but the power output by the rider is very different. What else can you use? You almost need to add force sensors to the pedal/foot interfaces...
 
  • #3
berkeman said:
You almost need to add force sensors to the pedal/foot interfaces..
That, in conjunction with a motion sensor on the crank, to tell the velocity of the foot, would allow you to calculate the power as long as you were measuring the tangential component of force. Perhaps two force meters at right angles could be used on each pedal and the outputs processed together with rotation information.. Alternatively, you could measure the chain tension and its speed.
 
  • #4
I think the professional devices to do this have a strain gauge in a special crank.
 
  • #6
CWatters said:
I think the professional devices to do this have a strain gauge in a special crank.
Yes, I agree, they would have to. And the strain gauges would need to read out the force in 2 dimensions (up/down and front/back) to capture all of the displacement forces going on. Bike "pedals" for performance bicycles are clip-ins or stirrups, which allow you to add force on the lift-up and push-forward parts of the pedal stroke, in addition to the push-down part of the stroke.

I've only recently learned to use the extra parts of the pedal stroke, and it definitely adds extra power... :smile:
 
  • #7
Hi All, Sorry for the late reply

Thanks for the responses! Allow me to clarify my project a bit:

I'm trying to mount sensors on stationary gym bikes, and use the data from the accelerometer, magnetometer, and gyroscope (9-axis motion) for further analysis. This means that I don't need to worry about having a sloped surface. Right now, I am focused on verifying that any data I receive is actually rotation/pedaling data. To do that, I have written a program which checks that the power in the y-axis (up/down) and x-axis (forwards/backwards) and sees that the average power over a short period of time is above some threshold (to be determined after I can accurately calculate power). Also, I recently realized I only need to calculate the power that the sensor experiences, and not necessarily the power that the rider exerts. Does this change the situation enough so that I can calculate power given time, acceleration, and mass?

In regards to my first two equations, I simply left out time on the RHS. Here's how it should be:

Power = Work/time = ½*m*v^2/time
Power * Time = ½*m*v^2
v = sqrt(2*Power*t/m)
a = dv/dt = sqrt(Power/2*m*t)
Power = a^2*(2*m*t)
 
  • #8
If you want to know the Power developed on a stationary bike, why not use a dynamometer? It measures the final power delivered to the road but it's very much a known art. It is also not too hard to measure the Power In by the cyclist - using gas analysis.
 
  • #9
sophiecentaur said:
If you want to know the Power developed on a stationary bike, why not use a dynamometer? It measures the final power delivered to the road but it's very much a known art. It is also not too hard to measure the Power In by the cyclist - using gas analysis.
From what I quickly looked up about dynamometers, they seem too big and expensive for what my project is trying to accomplish - a relatively cheap and automatic way to track gym exercise. Also, I'm trying to make this all electronic, so I would have no way of taking in data with a dynamometer.
 
  • #10
beterdenu said:
From what I quickly looked up about dynamometers, they seem too big and expensive for what my project is trying to accomplish - a relatively cheap and automatic way to track gym exercise. Also, I'm trying to make this all electronic, so I would have no way of taking in data with a dynamometer.
A stationary exercise bike almost certainly monitors rotation rate already. It may also be calibrated to know the resistance imposed at the current setting. I know the one I have at home is willing to display Watts. It presumably computes this by multiplying resistance by rotation rate and applying a simple decaying average.
 
  • #11
jbriggs444 said:
A stationary exercise bike almost certainly monitors rotation rate already. It may also be calibrated to know the resistance imposed at the current setting. I know the one I have at home is willing to display Watts. It presumably computes this by multiplying resistance by rotation rate and applying a simple decaying average.
Exactly. What does your "stationary bike" use for resistance? Or is it just a bike on free-rolling rollers? You just need to figure out what the resistance is on the different settings for your stationary bike, and use RPM as the variable that gives you the power. You don't really need the extra data of the power in the dirrerent parts of the pedal stroke, as long as you have the instantaneous RPM number and the resistance is constant.
 
  • #12
berkeman said:
Exactly. What does your "stationary bike" use for resistance? Or is it just a bike on free-rolling rollers? You just need to figure out what the resistance is on the different settings for your stationary bike, and use RPM as the variable that gives you the power. You don't really need the extra data of the power in the dirrerent parts of the pedal stroke, as long as you have the instantaneous RPM number and the resistance is constant.
Mine uses magnetic coupling, hidden under the housing so that the exact mechanism is not revealed. No idea how accurate it is.
 
  • #13
berkeman said:
Exactly. What does your "stationary bike" use for resistance? Or is it just a bike on free-rolling rollers? You just need to figure out what the resistance is on the different settings for your stationary bike, and use RPM as the variable that gives you the power. You don't really need the extra data of the power in the dirrerent parts of the pedal stroke, as long as you have the instantaneous RPM number and the resistance is constant.
I'm pretty sure the bike uses magnets to increase resistance, although I'm not absolutely certain as partner on this project is working on incorporating resistance into data analysis. Another thing I previously failed to mention is that I'm planning on not using any of the data that the bike already measures by itself (RPM, Speed, Time, etc) since the overall goal of this project is to create a central platform in which users can track ALL of their gym activity. This means I have to take in my own data as I have no electronic access to data that is built in on the biking platform.

I also want to note that my current goal is to simply check that any data I take is actually rotation and not just the pedal being randomly jerked around.

I guess a more general question is this:

How Can I relate Power and Acceleration in an equation?

Thanks!
 
  • #14
I am confused about your plans, though. You say you have no electronic access to the biking platform.
You appear to be wanting some form of measurement system that's attached to the person? This would be hard as it would have to involve multiple stress and motion sensors actually attached to the body. I mentioned gas analysis as a method for measuring rate of total work by the body. That is an established method, I think.
beterdenu said:
How Can I relate Power and Acceleration in an equation?
There are several formulae for Power. It is rate of doing work
Power = Force X Velocity
Power = Torque X Angular velocity
If you want 'acceleration' (?) involved then you can use
F = ma
The m would, presumably be your body mass (plus equipment) and measuring acceleration could be problematical and so why would you want to do that? Do you have a particular idea for this?
I feel that you need to specify in more detail what you envisage if you want to get any useful contributions from PF. There are many people who would be interested in the same sort of project, I am sure. There could be a lot of money in it for somebody to develop such a system.
 
  • #15
beterdenu said:
How Can I relate Power and Acceleration in an equation?
That is not enough for your project to succeed.

If you really need to make your school project work without any hooks into the stationary bike (or other exercise equipment), then you will need shoes and gloves that can sense force as well as position and acceleration. With that information you will be able to calculate the power involved. Without that information, you will not. Bottom line.
 
  • Like
Likes sophiecentaur
  • #16
beterdenu said:
Hi All, Sorry for the late reply

Thanks for the responses! Allow me to clarify my project a bit:

I'm trying to mount sensors on stationary gym bikes, and use the data from the accelerometer, magnetometer, and gyroscope (9-axis motion) for further analysis. This means that I don't need to worry about having a sloped surface. Right now, I am focused on verifying that any data I receive is actually rotation/pedaling data. To do that, I have written a program which checks that the power in the y-axis (up/down) and x-axis (forwards/backwards) and sees that the average power over a short period of time is above some threshold (to be determined after I can accurately calculate power). Also, I recently realized I only need to calculate the power that the sensor experiences, and not necessarily the power that the rider exerts. Does this change the situation enough so that I can calculate power given time, acceleration, and mass?

In regards to my first two equations, I simply left out time on the RHS. Here's how it should be:

Power = Work/time = ½*m*v^2/time
Power * Time = ½*m*v^2
v = sqrt(2*Power*t/m)
a = dv/dt = sqrt(Power/2*m*t)
Power = a^2*(2*m*t)
I don't see how the sensors you mention can be used to measure power. You need to measure the torque and angular velocity or a proxy for those. I can't think of a way to do it with an accelerometer. Where have you installed it?
 
  • #17
beterdenu said:
Power = Work/time = ½*m*v^2/time
Power * Time = ½*m*v^2
v = sqrt(2*Power*t/m)
a = dv/dt = sqrt(Power/2*m*t)
Power = a^2*(2*m*t)

Your application of these equations appears so wrong/confused I'm struggling to find a way to explain why they are wrong.

The work done by the rider against the friction brake is not 0.5mv^2.

I suspect you may well be recording data that looks like it's related to effort produced by the rider but i bet it's not. For example if a rider turns the pedals at a constant 1 revolution per second the data recorded by an accelerometer in the pedals will vary as the pedals rotate BUT it will not depend on the brake setting.
 

1. What is the role of friction in bike pedals?

Friction is an important force in bike pedals as it allows the rider to transfer their muscle power into rotational motion. When the pedal is pushed down, friction between the pedal and the rider's foot prevents it from slipping, allowing the force to be applied to the pedal and turn the wheel.

2. How does the shape of the pedal affect its efficiency?

The shape of the pedal affects its efficiency by changing the surface area in contact with the rider's foot. A larger surface area means there is more friction and thus more force can be applied to the pedal. However, a larger surface area also means that the pedal has to travel a longer distance to complete a full rotation, which can decrease efficiency.

3. What are the forces involved in pedaling a bike?

The main forces involved in pedaling a bike are muscular force from the rider's legs and the opposing forces of friction and air resistance. Muscular force is applied to the pedal, causing it to rotate and propel the bike forward. Friction between the pedal and the rider's foot prevents slippage, while air resistance acts against the forward motion of the bike.

4. How does the gear ratio affect the force needed to pedal a bike?

The gear ratio, which is the ratio of the number of teeth on the front and rear gears, affects the force needed to pedal a bike. A higher gear ratio means that the rider needs to apply more force to the pedals to turn the wheels, but each rotation of the pedals will result in a greater distance traveled by the bike.

5. What role does Newton's laws of motion play in pedaling a bike?

Newtons's laws of motion are fundamental principles in understanding the physics behind pedaling a bike. The first law, also known as the law of inertia, explains that an object will remain at rest or in uniform motion unless acted upon by an external force. This is why pedaling is necessary to keep a bike moving. The second law, or the law of acceleration, states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that the more force applied to the pedals, the greater the acceleration of the bike. Finally, the third law, or the law of action and reaction, explains that for every action, there is an equal and opposite reaction. When the rider pushes down on the pedal, the pedal pushes back with an equal force, propelling the bike forward.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
340
  • Mechanics
Replies
1
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
7
Views
1K
Replies
15
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
7
Views
3K
  • Engineering and Comp Sci Homework Help
2
Replies
49
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
766
  • Engineering and Comp Sci Homework Help
Replies
4
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
3K
Back
Top