What happens when a particle observes itself during quantum tunneling?

[sunmaggot]

The QM is saying that a particle in some potential pattern will have a wavefunction that describes the probability to find the particle. And then it also said that observation will make wavefunction collapse into measured value. For example, the electron in an atom will be in one position after measuring its position.

But I have a strange idea about this thing. The situation is that now there is a particle with energy E. There is a potential barrier in front of it which has potential V that is V>0. Also, 0<E<V. This means there can be quantum tunneling. Now if the particle can observe itself, what will it see when it performs quantum tunneling?

 

[phinds]

The QM is saying that a particle in some potential pattern will have a wavefunction that describes the probability to find the particle. And then it also said that observation will make wavefunction collapse into measured value. For example, the electron in an atom will be in one position after measuring its position.

But I have a strange idea about this thing. The situation is that now there is a particle with energy E. There is a potential barrier in front of it which has potential V that is V>0. Also, 0<E<V. This means there can be quantum tunneling. Now if the particle can observe itself, what will it see when it performs quantum tunneling?

A particle observing itself is a meaningless concept. Any "observation" would have to be by an outside agent.

 

[sunmaggot]

A particle observing itself is a meaningless concept. Any "observation" would have to be by an outside agent.

maybe I didn't ask it clearly. Actually I am thinking that the particle defined its own position and made its own wavefunction collapse. So it would not have anymore chance to quantum tunnel? But it should tunnel because for outside observer, the wavefunction includes quantum tunneling.

 

[phinds]

I am thinking that the particle defined its own position and made its own wavefunction collapse

I have no idea what that means.

 

[rootone]

... I am thinking that the particle defined its own position ...

Sentient subatomic particles with free will?

 

[Nugatory]

And then it also said that observation will make wavefunction collapse into measured value.

This is one of the most common misunderstandings of quantum mechanics. "Observation", in the ordinary English-language meaning of the word, has nothing to do with whether the wave function collapses; just about any interaction with something large enough to be considered a classical object will collapse the wave function. (The confusion with observation comes about because the lab equipment that we'd use to observe the position has to be a reasonably large classical object).

Now if the particle can observe itself...

But it can't. We need an interaction with a sufficiently large classical object to collapse the wave function, and we don't have that here.

 

[StevieTNZ]

An interaction between a microscopic object and another microscopic object simply entangles them. I don't think a microscopic object can observe itself, as it may mess with QM predictions.

 

[sunmaggot]

I see, so the condition in my question actually cannot happen. Thank you for the replies.