- #1
bjnartowt
- 284
- 3
what's the standard "name" of this equation so i can look up how to solve it?
Find the solution to
[tex]\left( {\frac{1}{{{r^2}}}\frac{d}{{dr}}\left( {{r^2}\frac{d}{{dr}}} \right) - \frac{{\ell (\ell + 1)}}{{{r^2}}} + {k^2}} \right){g_{k\ell }}(r,r') = - \frac{1}{{{r^2}}}\delta (r - r')[/tex]
subject to the boundary conditions: [tex]{g_{k\ell }}(0,r') = 0{\rm{ and }}{g_{k\ell }}(r,r')\~{\textstyle{1 \over r}}\exp ({\bf{i}}kr){\rm{ for large r}}[/tex]
see problem statement.
I think this is "of the form",
[tex]L{g_{k\ell }}(r,r') = \delta (r - r')[/tex]
...where L is a linear operator. What is the "name" of this equation (e.g., is it an "inhomogeneous linear ODE"?). I need to know the "name" so I can look up the solution method somewhere. (I didn't have the best differential equations course).
***see attached .pdf for LaTeX stuff that got garbled...***
Homework Statement
Find the solution to
[tex]\left( {\frac{1}{{{r^2}}}\frac{d}{{dr}}\left( {{r^2}\frac{d}{{dr}}} \right) - \frac{{\ell (\ell + 1)}}{{{r^2}}} + {k^2}} \right){g_{k\ell }}(r,r') = - \frac{1}{{{r^2}}}\delta (r - r')[/tex]
subject to the boundary conditions: [tex]{g_{k\ell }}(0,r') = 0{\rm{ and }}{g_{k\ell }}(r,r')\~{\textstyle{1 \over r}}\exp ({\bf{i}}kr){\rm{ for large r}}[/tex]
Homework Equations
see problem statement.
The Attempt at a Solution
I think this is "of the form",
[tex]L{g_{k\ell }}(r,r') = \delta (r - r')[/tex]
...where L is a linear operator. What is the "name" of this equation (e.g., is it an "inhomogeneous linear ODE"?). I need to know the "name" so I can look up the solution method somewhere. (I didn't have the best differential equations course).
***see attached .pdf for LaTeX stuff that got garbled...***