- #1
cristianbahena
- 16
- 1
In a barrier potential with sections: I: V(x)=0 (x<-a), II:V(x)=V (-a<x<a) and III:V(x)=0 (a<x) you can write the solution in this form:
Ψ(x)=Ae^(ikx)+Be^(-ikx) (x<-a)
Ψ(x)=Ce^(ik'x)+De^(-ik'x) (-a<x<a)
Ψ(x)=Ee^(ikx) (a<x)
and with boundary conditions solve,
but why do you can write this solution in this form:
Ψ(x)=Ae^(ikx)+DAR^e(-ikx) (x<-a)
Ψ(x)=ACe^(ik'x)+AD^(-ik'x) (-a<x<a)
Ψ(x)=ATe^(ikx) (a<x)
with R reflection coefficient and T transmission coefficient
Ψ(x)=Ae^(ikx)+Be^(-ikx) (x<-a)
Ψ(x)=Ce^(ik'x)+De^(-ik'x) (-a<x<a)
Ψ(x)=Ee^(ikx) (a<x)
and with boundary conditions solve,
but why do you can write this solution in this form:
Ψ(x)=Ae^(ikx)+DAR^e(-ikx) (x<-a)
Ψ(x)=ACe^(ik'x)+AD^(-ik'x) (-a<x<a)
Ψ(x)=ATe^(ikx) (a<x)
with R reflection coefficient and T transmission coefficient