Why Does the Escape Velocity Decrease as Mass Increases in an Electric Field?

In summary, the conversation discusses the concept of escape velocity in the context of electric fields. It is observed that escape velocity decreases as mass increases, which is explained by the fact that the electric force does not depend on the mass of the object in motion, but the inertia and kinetic energy do. This is in contrast to the gravitational field, where the equivalence principle cancels out the effects of mass in the equations for escape velocity. The electric potential energy change remains fixed by the charges.
  • #1
kickthatbike
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Upon applying the method of finding escape velocity to the E-field, I end up with:

[itex]\sqrt{\frac{2kQq}{rm}}[/itex]

What I don't understand, conceptually, is why escape velocity decreases as mass increases, in the electric field. What property is actually taking place here?
 
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  • #2
More kinetic energy is invested in a mass for a given velocity if the mass is larger. When dealing with the gravitational field, the force providing the potential energy scaled with the mass, but the inertia and thus the KE of the moving mass also scaled with the mass. This is due to what's known as "the equivalence principle", wherein gravitational mass and inertial mass are numerically the same for all matter. The effects cancel in the equations and the mass of the "escaping" body drops out of the equation for escape velocity.

With the electric scenario there's no equivalence principle "hiding" the effect of the mass of the moving object in the relationship. The electric force does not depend upon the mass of the object in motion, but the inertia and thus KE still depend upon that mass. So, for a given v: small mass, small inertia and small KE. Large mass yields large inertia and KE. The electric potential energy change, which the KE must balance for asymptotic escape, remains fixed by the charges.
 
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  • #3
You explained that very well. Thank you very much.
 

1. What is escape velocity of E-field?

Escape velocity of E-field, also known as the threshold velocity, is the minimum speed required for a charged particle to escape from the influence of an electric field. It is calculated by equating the kinetic energy of the particle to the potential energy of the electric field.

2. How is escape velocity of E-field calculated?

The escape velocity of E-field is calculated using the formula: vesc = √(2qE/m), where q is the charge of the particle, E is the magnitude of the electric field, and m is the mass of the particle.

3. What factors affect the escape velocity of E-field?

The escape velocity of E-field is affected by the strength of the electric field, the charge of the particle, and the mass of the particle. A stronger electric field or a larger charge will result in a higher escape velocity, while a larger mass will result in a lower escape velocity.

4. How does the escape velocity of E-field relate to gravity?

Escape velocity of E-field and escape velocity due to gravity are similar concepts in that they both represent the minimum speed required for an object to escape from an external force. However, they differ in their calculations and the type of force they are escaping from.

5. What is the significance of the escape velocity of E-field?

The escape velocity of E-field is an important concept in understanding the behavior of charged particles in electric fields. It helps in predicting the motion of particles and determining the conditions for particles to escape from the influence of an electric field. It also has practical applications in fields such as aerospace engineering and particle physics.

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