Why isn't the light signal from a falling spaceship Doppler shifted?

In summary: Sally is higher up and not falling, then she sees the sum of increasing gravitational redshift and classical Doppler redshift, because Harry is falling and accelerating away from her. Sally is also accelerating herself, so she would see the classical Doppler shift and an increased gravitational redshift. Sally is lower down and Harry is accelerating upwards, so she sees the increased gravitational redshift and no classical Doppler shift. Sally is right next to Harry, so she sees the classical Doppler shift and no increased gravitational redshift.
  • #1
sweetdreams12
9
0
Just some conceptual ideas that I don't understand

A spaceship starts falling under gravity with an acceleration g as measured by an observer Barry at rest on Earth. At the instant that the ship starts to fall, an astronaut Harry at the base of the rocket ship sends a light signal of frequency w vertically upward to another astronaut Sally a distance h above.

Barry argues that the light signal reaching Sally ought to be Doppler shifted toward the blue. This Doppler shift Δw is given by (Δw/w)_Doppler = (Δu/c)

where Δu is the velocity of the rocket ship after a time Δt = (h/c)

But Sally does not see this shifted frequency. So why is this? What compensates for the Doppler shift in frequency? And if another observer (let's call her Kelly) was to see the red-shifted light, what is required for her?
 
Physics news on Phys.org
  • #2
Hint: the regular doppler shift equations assume inertial reference frames.
 
  • #3
Simon Bridge said:
Hint: the regular doppler shift equations assume inertial reference frames.

meaning they are non-accelerating...so Sally isn't accelerating hence she can't see the shifted frequency?
 
  • #4
No - doppler shift is noticeable in non-accelerated frames.
That is how it is usually worked out.

I mean Harry and Sally are both following a special path in space-time.
What level are you doing this at?
 
  • #5
sweetdreams12 said:
Just some conceptual ideas that I don't understand

A spaceship starts falling under gravity with an acceleration g as measured by an observer Barry at rest on Earth. At the instant that the ship starts to fall, an astronaut Harry at the base of the rocket ship sends a light signal of frequency w vertically upward to another astronaut Sally a distance h above.

Barry argues that the light signal reaching Sally ought to be Doppler shifted toward the blue. This Doppler shift Δw is given by (Δw/w)_Doppler = (Δu/c)

where Δu is the velocity of the rocket ship after a time Δt = (h/c)

But Sally does not see this shifted frequency. So why is this? What compensates for the Doppler shift in frequency? And if another observer (let's call her Kelly) was to see the red-shifted light, what is required for her?

If I correctly understand your set-up:

x Sally (for simplification: also falling down from t=0)
¦ continuous light signal sent up by Harry
x Harry (falling down from t=0)

x Barry (on Earth)
---------

1. Barry could argue that the light for Sally ought to be blue-shifted, based on the Doppler effect for accelerated objects: Sally is falling faster than Harry's light emitter at the moment of emission, thus a blueshift.

2. Sally is also higher up than Harry. The higher gravitational potential results in a blueshift of her eye's colour reference. According to the equivalence principle, this blueshift due to gravitation is equal to the Doppler effect due to acceleration, and thus Sally does not see a shifted frequency.

Next you ask about "the red-shifted light"; however, it's not clear in what situation. Maybe you want to know in what situation Kelly, maybe also straight above Harry, should be to see the light redshifted.

If Kelly is higher up and not falling, then she'll see the sum of increasing gravitational redshift and classical Doppler redshift, because Harry is falling and accelerating away from her.
PS: I assumed "non-relativistic" speed.
 
Last edited:
  • #6
sweetdreams12 said:
meaning they are non-accelerating...so Sally isn't accelerating hence she can't see the shifted frequency?
The rocket frame, where the astronauts are both at rest, is inertial. So based on their rest frame the astronauts conclude there should be no Doppel-Shift.

The surface observes frame is not inertial. He sees a local gravitational field and gravitational time dilation, which cancels the Doppel-effect, from the velocity difference emitter (during emission) and receiver (during receive). So he also concludes there should be no detectable Doppel-Shift.
 
  • #7
Barry reckons that Sally should see a doppler shift because they are accelerating - so Sally intercepts the wavefronts from Barry's signal faster, for a higher frequency. However, Harry and Sally are stationary wrt each other, so they are not at all surprised that Sally reports the same wavelength that Harry sent.

What gives? Either there was a doppler shift or their wasn't!

Barry thinks a bit and slaps his forehead: "of course!" he cries, "the doppler shift was compensated by..." something something something ... which is what the question is asking about. What is the something something that Barry realized?
Barry expects Sally to report a blue-shift ... she didn't... therefore there must have been a compensating red shift. What would cause that?
What is present in Barry's frame that is not present in the ship frame? Starts with "g".

For Sally to see a blue shift - she needs to have a different relationship to Harry. If she broke up with him, he'd get blue quite fast... but I think the easiest answer is to figure what direction shift Barry sees. There's several ways that Sally could see a bluer signal: how many can you think of?

There are a few wrinkles since the description does not mention the relative angular motion.
One is tempted to imagine the ship is falling directly towards Barry - but we remember that Barry's reference frame is rotating wrt the center of mass frame of the Earth.

This isn't the homework section, so we can go a bit easier on you here... but it is still more useful for you if you make certain connections yourself.
 

What is Doppler shift frequency?

Doppler shift frequency is the change in frequency of a wave (such as sound or light) caused by the relative motion of the source and observer. It is commonly observed with sound waves from moving vehicles or with light waves from celestial objects.

How is Doppler shift frequency calculated?

The Doppler shift frequency is calculated using the equation f' = f(v + V)/v, where f is the original frequency, v is the speed of the wave in the medium, V is the relative velocity of the source and observer, and f' is the shifted frequency. This equation applies to both sound and light waves.

What is the difference between the Doppler effect and Doppler shift frequency?

The Doppler effect refers to the perceived change in frequency of a wave due to the relative motion between the source and observer. Doppler shift frequency specifically refers to the change in frequency of a wave due to the Doppler effect.

What is a positive and negative Doppler shift frequency?

A positive Doppler shift frequency occurs when the source and observer are moving towards each other, causing the observed frequency to be higher than the original frequency. A negative Doppler shift frequency occurs when the source and observer are moving away from each other, causing the observed frequency to be lower than the original frequency.

What are some real-life applications of Doppler shift frequency?

Doppler shift frequency has many practical applications, such as determining the speed of moving objects (such as vehicles), measuring the rotation of celestial objects, and in medical imaging techniques such as ultrasound. It is also used in weather forecasting, as changes in the frequency of sound waves can indicate the presence of storms or wind patterns.

Similar threads

  • Special and General Relativity
2
Replies
60
Views
5K
  • Special and General Relativity
Replies
28
Views
2K
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Special and General Relativity
Replies
5
Views
2K
  • Special and General Relativity
Replies
4
Views
2K
  • Electromagnetism
Replies
4
Views
1K
  • Special and General Relativity
2
Replies
35
Views
5K
  • Introductory Physics Homework Help
Replies
6
Views
814
  • Special and General Relativity
Replies
12
Views
2K
Back
Top