symbolipoint said:My thought may have been off-track a little bit. Maybe you do have the reactions that are needed, but the titration is intended to find the excess iodine remaining from the first reaction.
This is because the balanced chemical equation for the reaction between (S2O3 2-) and ( MnO4-) has a 1:5 mole ratio. This means that for every 1 mole of ( MnO4-), 5 moles of (S2O3 2-) are needed for the reaction to occur. Therefore, the number of moles of (S2O3 2-) is always equal to the number of moles of ( MnO4-) times 5.
The mole ratio between (S2O3 2-) and ( MnO4-) can be determined from the balanced chemical equation for the reaction between the two substances. The coefficients of the two compounds in the equation represent the mole ratio. In this case, the coefficient of (S2O3 2-) is 5, indicating that the mole ratio between (S2O3 2-) and ( MnO4-) is 5:1.
Yes, the mole ratio between (S2O3 2-) and ( MnO4-) is always 5:1 as long as the chemical reaction remains the same. This is because the coefficients in a balanced chemical equation represent the relative number of moles of each substance involved in the reaction.
No, the number of moles of (S2O3 2-) can never be greater than the number of moles of ( MnO4-) in this reaction. This is because the mole ratio between the two substances is 5:1, meaning that for every 1 mole of ( MnO4-), there must be 5 moles of (S2O3 2-) present for the reaction to occur.
Having the correct mole ratio in a chemical reaction is important because it ensures that the reaction proceeds efficiently and all of the reactants are consumed. If the mole ratio is not correct, there may be excess reactants or incomplete reaction, leading to lower yield and potentially affecting the quality of the final product. Additionally, the mole ratio is needed to accurately calculate the amount of products produced in the reaction.