- #1
George317
✱✱ template missing after move from technical forum to homework help forum ✱✱
in our laboratory class we made a simple bridge rectifier circuit like this
then we replaced D1 and D2 with resistors, and when we connected the probes of the oscilliscope on the load resistor it showed a DC output something like this(sorry for the bad drawing)
can you guys explain why it produces that output voltage? like what happens in the postive cycle to produce that waveform and what happens in the negative that would result with that wave.
may attempt in answering this:
in the positive cycle D4 and D3 are both reversed bias the current would have to go through the 2 resistor(previouslyD1 & D2) and RL hence the low value in the load.
while in the negative cycle it appears bigger because current does not want to go to the 2 resistors(?) because of "the current goes to the least resistance thing" hence its only goes to D2 -> RL -> D4 -> source.
then we replaced D1 and D2 with resistors, and when we connected the probes of the oscilliscope on the load resistor it showed a DC output something like this(sorry for the bad drawing)
can you guys explain why it produces that output voltage? like what happens in the postive cycle to produce that waveform and what happens in the negative that would result with that wave.
may attempt in answering this:
in the positive cycle D4 and D3 are both reversed bias the current would have to go through the 2 resistor(previouslyD1 & D2) and RL hence the low value in the load.
while in the negative cycle it appears bigger because current does not want to go to the 2 resistors(?) because of "the current goes to the least resistance thing" hence its only goes to D2 -> RL -> D4 -> source.
Last edited by a moderator: