- #1
dRic2
Gold Member
- 883
- 225
- Homework Statement
- .
- Relevant Equations
- .
Hi, this is not an exercise. In some lecture notes the authors states that from elementary EM I should familiar with the fact that the work associated with polarization and magnetization of a material is given by ##\delta W = E dP## and ##\delta W = BdM##. I have to admit that I am super rusty about EM so I was wondering if my reasoning to get here is correct.
- polarization: from Lorentz force without B field and identifying with ## d \mathbf l## the displacement from the "equilibrium position" (P = 0) of the bound charges, I get ## \mathbf F \cdot d \mathbf l = (q_{bound} + q_{ext}) \mathbf E \cdot d \mathbf l ##. Since I'm considering a neutral material ##q_{ext} = 0##, I can write ## \delta W = \mathbf E \cdot ( q_{bound} d \mathbf l )##. Here I naively identify ##q_{bound} d \mathbf l = d \mathbf P## and conclude ## \delta W = \mathbf E \cdot d \mathbf P##
- magnetization: I recall that for a magnetic dipole ## \mathbf m##, ## U = - \mathbf m \cdot \mathbf B##. Since the filed is supposed to be constant I just take the differential and it follows immediately that ## \delta W = \mathbf B \cdot d \mathbf m##
- polarization: from Lorentz force without B field and identifying with ## d \mathbf l## the displacement from the "equilibrium position" (P = 0) of the bound charges, I get ## \mathbf F \cdot d \mathbf l = (q_{bound} + q_{ext}) \mathbf E \cdot d \mathbf l ##. Since I'm considering a neutral material ##q_{ext} = 0##, I can write ## \delta W = \mathbf E \cdot ( q_{bound} d \mathbf l )##. Here I naively identify ##q_{bound} d \mathbf l = d \mathbf P## and conclude ## \delta W = \mathbf E \cdot d \mathbf P##
- magnetization: I recall that for a magnetic dipole ## \mathbf m##, ## U = - \mathbf m \cdot \mathbf B##. Since the filed is supposed to be constant I just take the differential and it follows immediately that ## \delta W = \mathbf B \cdot d \mathbf m##