Working out a point / segment on a sphere

In summary, the problem being discussed is the placement of a segment line on a spinning sphere in order for two points, a1 and a2, to always be in a shaded area on the sphere. The angle of the axis and the distance of the segment line from the center line determine the percentage of time the points spend in the shaded area. The goal is to determine the distance of the segment line for a 75% shaded area and a 25% non-shaded area. The solution involves trigonometry and finding the midpoint of a line that intersects point a3 on the sphere.
  • #1
rede96
663
16
Hi, I was hoping someone could help me figure out the problem below. It is a bit of a long winded questions so please bare with me!

If you look at Fig 1 below, I have a sphere that spins about an axis in a clockwise direction. (the direction of the spin doesn't really matter) In this case the axis is pointing directly upwards, so the angle is 0 degrees.

You will notice the sphere also has a shaded area which covers the top half of the sphere.

If a put a 'segment line' perpendicular to the axis, which is at a distance x from the centre line, it will intersect the surface of the sphere at 2 points which I have labelled a1 and a2.

I know that as long as I place the segment line above the centre line then points a1 and a2 will always be in the shaded area as the sphere rotates.
fig_1.jpg

Now if I turn the axis by 90 degrees as in Fig 2 below, I can put a segment line at any distance x from the centre line, perpendicular to the axis, and points a1 and a2 will spend 50% of the time in the shaded area and 50% of the time in the unshaded area, as the shaded area doesn't rotate with the axis.
fig_2.jpg

So, I now turn the axis to 60 degrees as in Fig 3 below and I want to know at what distance x would the segment line need to be away from the centre line so points a1 and a2 would always be in the shaded area as the sphere turns.

I can do a bit of trig here and make a right angled triangle between the centre point of the circle, point a2 and the point where the segment line intersects the axis. I know the angle is 30 degrees and I know the radius r, so Cos 30 r = x

fig_3.jpg


In Fig 4 below the axis is again at 60 degrees. My question is at what distance x from the centre line would I need to place the segment line so points a1 and a2 would spend 75% of the time in the shaded area and 25% of the time in the unshaded area as the sphere rotates. I just can't figure this out!

Any help would be much appreciated.

fig_4.jpg
 
Last edited:
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  • #2
I would suggest starting with a picture of the circle a1 and a2 trace out in their rotation. Consider where the shaded region will fall depending on your variable, then find the cutoff line which divides the circle into parts of 1/4:3/4.
 
  • #3
rede96 said:
Hi, I was hoping someone could help me figure out the problem below. It is a bit of a long winded questions so please bare with me!

Sorry, I never disrobe with strangers.
 
  • #4
LCKurtz said:
Sorry, I never disrobe with strangers.
haha :) Don't blame you!

RUber said:
would suggest starting with a picture of the circle a1 and a2 trace out in their rotation. Consider where the shaded region will fall depending on your variable, then find the cutoff line which divides the circle into parts of 1/4:3/4.

Thanks for the reply but to be honest I’m not sure how that will solve it?

On the sphere, where the line a1,a2 crosses the diameter of the shaded area, (the line that runs horizontally across the middle of the circle) let’s call that point a3.

I know that I can split any circle into 1/4:3/4 easily enough, it is just 90 degrees and 270 degrees along the circumference. This would be equivalent to the path a1 and a2 take. I also know that if I draw a line across any of the quadrants of that circle, the mid-point of that line that must intersects point a3 on the sphere.

But what I have no way of knowing (Or haven’t figured it out yet!) is how big the diameter a1,a2 must be so when that circle a1, a2 sits in the sphere it fits in the right place for a1 and a2 to travel around the sphere in the shaded area 75% and non shaded 25%

Anyway, up for work early, so will try and give it some more through during the week.
 

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1. How do you determine the coordinates of a point on a sphere?

To determine the coordinates of a point on a sphere, you need to know the radius of the sphere and the angle of rotation around the sphere's axis. This can be done using spherical coordinates, which use two angles (θ and φ) to indicate the location of a point on a sphere.

2. What is the formula for finding the distance between two points on a sphere?

The formula for finding the distance between two points on a sphere is known as the haversine formula. It takes into account the radius of the sphere and the latitudes and longitudes of the two points to calculate the shortest distance between them.

3. How do you find the intersection point of two segments on a sphere?

To find the intersection point of two segments on a sphere, you can use the spherical triangle formula. This involves calculating the angles and sides of the spherical triangle formed by the two segments and the center of the sphere. The intersection point will be where the two segments intersect on the surface of the sphere.

4. Can a segment on a sphere ever be a straight line?

No, a segment on a sphere can never be a straight line. This is because a straight line on a 2-dimensional surface (like a piece of paper) is different from a straight line on a 3-dimensional surface (like a sphere). On a sphere, a straight line is actually a great circle, which is the largest circle that can be drawn on the surface of the sphere.

5. How do you calculate the area of a segment on a sphere?

To calculate the area of a segment on a sphere, you can use the spherical cap formula. This formula takes into account the radius of the sphere and the height of the segment (which can be calculated using the haversine formula). The resulting area will be in square units, such as square meters or square inches.

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