Yo-yoing over the harmonic oscillator

[DiracPool]

I've been looking around and trying to figure it out, but I can't seem to figure out how the cosine function get's into the solution to the HO equation d2x/dt2=-kx/m. I know this is extremely basic, but could someone indulge me?

 

[Physics2.0]

The second derivative of -cosθ is equal to cosθ. Because [-cosθ]' = -sinθ and [-sinθ]' = cosθ so [-cosθ]'' = cosθ.
Maybe this is also helpfull: http://www.wolframalpha.com/input/?i=x''+=+-x

 

[grzz]

It is not so difficult to use a better notation!

Try to see whether x = acos(bt), where a and b are constants, fits with the equation

\frac{d^{2}x}{dt^{2}} = -(positive constant)x.