Recent content by 4570562
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Why Is There a Negative Sign in the Work-Energy Equation?
Okay I think I figured it out. Suppose toward a contradiction that U=f=-mgy. Going back to the ball example that would mean U_{a}=-mgh K_{a}=0 U_{b}=-mg(-4.5+h)=4.5mg2-mgh K_{b}=4.5mg2 But that would violate conservation of energy since U_{a}+K_{a}≠U_{b}+K_{b}. However...- 4570562
- Post #4
- Forum: Introductory Physics Homework Help
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Why Is There a Negative Sign in the Work-Energy Equation?
Let's take an example. Suppose you drop from rest a ball of mass m and let it fall for 3 seconds. You want to find the amount of work that gravity does on the object. There are three ways you could proceed. 1) Use W=\int\vec{F}\cdotd\vec{r} the line integral method. (Note that this...- 4570562
- Post #3
- Forum: Introductory Physics Homework Help
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Why Is There a Negative Sign in the Work-Energy Equation?
Homework Statement My calculus book gives the following definition of a conservative vector field: A vector field F is called conservative if there exists a differentiable function f such that F=\nablaf. The function f is called the potential function for F. It then gives the...- 4570562
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- Energy Potential Potential energy
- Replies: 3
- Forum: Introductory Physics Homework Help
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Help understanding the gradient
Thank you very much. I knew it was something easy like that. I didn't see it because I kept going back to the limit definition of the derivative where it doesn't matter if you are interpreting the slope formula from the positive or negative direction. It seems that direction doesn't...- 4570562
- Post #3
- Forum: Calculus and Beyond Homework Help
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Help understanding the gradient
Homework Statement The evaluated partial derivative of f(x,y) with respect to x is -16 and 6 with respect to y at some point (x0,y0). What is the vector specifying the direction of maximum increase of f? Homework Equations The direction of maximum increase of f is given by...- 4570562
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- Gradient
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Directional Derivative for f(x)
Maybe you can take the gradient of a function of a single variable but just not the directional derivative? It seems to me now that the directional derivative wouldn't make any sense for f(x) because you can't vary x in a "direction". Varying x in the negative or positive direction still gives...- 4570562
- Post #5
- Forum: Calculus and Beyond Homework Help
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What is the Limit of Summation Notation for a Given Interval?
Seems right to me.- 4570562
- Post #2
- Forum: Calculus and Beyond Homework Help
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Directional Derivative for f(x)
Homework Statement Is it possible to take the directional derivative of a function of a single variable? For example if f(x)=sinx and the unit vector specifying the direction is u=<cos pi/4, sin pi/4>, then could you say that duf = .5*(sqrt2)*cosx ?- 4570562
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- Derivative Directional derivative
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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How to solve for probability given density function
Not quite sure, but maybe you do ∫f(y) dy from 0 to 10/45?- 4570562
- Post #2
- Forum: Calculus and Beyond Homework Help
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Magnitude of Cross Product Mismatch
Thank you so much. cos theta = .5 implies that theta is pi/3 , which would make it work both ways. I can't tell you how long I have been just staring at this problem. Thanks.- 4570562
- Post #3
- Forum: Calculus and Beyond Homework Help
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Magnitude of Cross Product Mismatch
Homework Statement Find the magnitude of the vector product w ⃗x u, where w=<1,0,1> and u=<1,1,0>. Homework Equations ||w x u|| = ||w|| ||u|| sin θ cos θ = \frac{w.u}{||w|| ||u||} The Attempt at a Solution w ⃗x u ⃗= -i ̂+j ̂+k ̂ ‖||w ⃗x u|| ⃗ ‖= √3 but...- 4570562
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- Cross Cross product Magnitude Product
- Replies: 2
- Forum: Calculus and Beyond Homework Help