Recent content by 5ymmetrica1

Homework Statement create an algorithm for a Fibonacci sequence that will return the f value in f(n) = f(n-1)+f(n-2) Homework Equations f(n) = f(n-1)+f(n-2) The Attempt at a Solution I have tried several ways to create an algorithm that will sum the two previous numbers but always end up...

what am I substituting though? Do I substitute with f(x) or dy/dx?

So that problem worked out fine, But the next question asks me to find the equation to a tangent of ax2+by2= c at the point where x = d So how would I approach this? Ive got as far as... d/dy [ax2+by2] = c dy/dx = -2x/2y = -x/y by now I need the coordinates, I know that...

So if I want it to pass through the origin I can find the slope by using 1.732/1.5 = 1.155 then I can use the equation y = ax+b where a = 1.155 and b = 0 (y-intercept) to give me y = 1.155x+0 does this look correct?

Homework Statement Find the equation of the tangent, and the line which passes through the origin to the point where x= 3/2 4x2+9y2 = 36Homework Equations The Attempt at a Solution Using implicit differentiation d/dy [4x2+9y2] =36 8x+18y dy/dx = 0 dy/dx = -8x/18y Coordinates are (1.5...

yeah I worked it out today, I think this problem just got the better of me this week lol. Thanks for your help everyone!

y = a(-ab/(1+a2)) + b I think this works? But I'm still not sure how I get -a from this answer

Thanks, yes I understand why now. so x = -ab / (1+a2) ?

Actually I've been away from my studies for a long time due to some health issues and have been struggling to get myself back to where I was 6 months ago, I have finals coming up too which is worrying! Is my last post correct?

so x + a^2(x) = a^2(x) I hope so anyway or I'm going to bury my head in the sand :cry:

I know how to do it with numbers but the a^2 is confusing me, if I have a^2 amounts of (x) and I add (x) x is the coefficient in the first and second term isn't it? if I add x and x together I have 2x :confused:

so x + a^2(x) would be 2a^2(x)?

so I get x + a2x = -ab a2(2x) = -ab 2x = -ab / a2 = -b/a x = (-b/a)/2

You mean like this? x=−2⋅3−2 2 x -2(3) -22x = x -2(3) = 22(2x) -6 = 4(2x) 8x = -6 x = -6/8 = -3/4

so I now know I need to get a final result of -a, which proves my original hypothesis that the value of the ratio is equal to the value of a in the equation y = ax+b and it involves using the equation √x2 + a2x2+2axb+b2 but I'm stuck from here. Can anyone offer me any help here. This...