Make a conjecture about y = ax+b

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  • #31
5ymmetrica1 said:
Actually I've been away from my studies for a long time due to some health issues and have been struggling to get myself back to where I was 6 months ago, I have finals coming up too which is worrying!

Is my last post correct?

No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.
 
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  • #32
Dick said:
No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.

Thanks, yes I understand why now.

so x = -ab / (1+a2) ?
 
  • #33
5ymmetrica1 said:
so x = -ab / (1+a2) ?

yup! :smile:

so y = … ?

and the slope = … ? :wink:
 
  • #34
tiny-tim said:
yup! :smile:

so y = … ?

and the slope = … ? :wink:

y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer
 
  • #35
5ymmetrica1 said:
y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer

you seem to be frightened by algebra

grit your teeth and expand a(-ab/(1+a2)) and you should see how -a pans out :wink:
 
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  • #36
yeah I worked it out today, I think this problem just got the better of me this week lol.

Thanks for your help everyone!
 
  • #37
good! :smile:

but since you need the practice, now try it another way …

your professor told you to find the the slope (let's call it "k") by finding the distance as a function of x, and to differentiate wrt x

instead, try finding the distance as a function of k, and differentiating wrt k (which will give you k directly, and may be quicker)

ie for the slope y = kx, find the coordinates where it intersects y = ax + b (both as a function of k), and then minimise that

to practise your algebra, show us what you get :smile:

(and which method do you think is quicker?)​
 

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