Recent content by _chris_

that's what i did. 59680 / (1360.7)(9.8)(sin(15)) = ...17.3 i think i screwed up when i put it in the calculator ha. I'm sorry. that seems good to me. thanks a lot!

how did you get that?? it's much more realistic than my answer. heh. and a lot of answers we get seem to be unrealistic. i dunno...an 80-hp engine is pretty small. but yeah...i have no idea how you came to that answer.

3451 m/s? i'm pretty sure i got lost early on there... if i were to arbitrarily pick some point reasonably far up the slope, would i be able to assume that it had reached its maximum velocity? probably not. bah.

this is driving me up a wall. i've made no progress

oh good lord. I've now made a complete fool of myself. at first i thought there was no way to edit the topic, which i now see that there is. i also thought you were able to delete threads you started. and you cannot. so uh. that's the reason for my uh...idiocy. i apologize.

a 1360.7 kg car has an engine which can deliver 59,680 watts to the rear wheels. what is the max. velocity at which the car can climb a 15-degree hill? i have no idea how to solve this. immediate help would be GREATLY appreciated! the work i have done was setting up a triangle with the...

oh great. now i read the sticky topic. should have done that before. ha! well anyway the work i have done was setting up a triangle with the mass as the hypotenuse...and found the side opposite the 15-degree angle to be 352.17...and from there i am just lost. i don't see how using the...

a 1360.7 kg car has an engine which can deliver 59,680 watts to the rear wheels. what is the max. velocity at which the car can climb a 15-degree hill? i have no idea how to solve this. immediate help would be GREATLY appreciated!