Problem involving power, mass, incline, and finding a max. velocity

AI Thread Summary
To determine the maximum velocity of a 1360.7 kg car climbing a 15-degree incline with an engine power of 59,680 watts, one must consider the forces acting on the car, including gravitational force and engine power. The gravitational force can be calculated using the car's weight and the sine of the incline angle. The maximum velocity can then be found by equating the power output of the engine to the work done against gravity. The discussion highlights confusion about the problem-solving process and the urgency due to an upcoming test. Overall, the participant expresses frustration over their lack of progress and understanding of the physics involved.
_chris_
Messages
8
Reaction score
0
a 1360.7 kg car has an engine which can deliver 59,680 watts to the rear wheels. what is the max. velocity at which the car can climb a 15-degree hill?

i have no idea how to solve this. immediate help would be GREATLY appreciated!

the work i have done was setting up a triangle with the mass as the hypotenuse...and found the side opposite the 15-degree angle to be 352.17...and from there i am just lost.

i don't see how using the given numbers could help find a maximum velocity. we have a test tomorrow, and this question is on it. our teacher said he would give no advice as to how to solve it. he actually suggested that we find a place much like this one in order to figure out what to do.
 
Physics news on Phys.org
oh good lord. I've now made a complete fool of myself.

at first i thought there was no way to edit the topic, which i now see that there is. i also thought you were able to delete threads you started. and you cannot.

so uh. that's the reason for my uh...idiocy. i apologize.
 
this is driving me up a wall.

i've made no progress
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top